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Basile [38]
3 years ago
7

How do I write a polynomial when given the zeros​

Mathematics
2 answers:
Blababa [14]3 years ago
8 0

Answer:

Subtract the first zero from x and enclose it in parentheses. This is the first factor. For example if a polynomial has a zero that is -1, the corresponding factor is x - (-1) = x + 1.

Raise the factor to the power of the multiplicity. For instance, if the zero -1 in the example has a multiplicity of two, write the factor as (x +1)^2.

Repeat Steps 1 and 2 with the other zeros and add them as further factors. For instance, if the example polynomial has two more zeros, -2 and 3, both with multiplicity 1, two more factors -- (x +2) and (x -3) -- must be added to the polynomial. The final form of the polynomial is then ((x +1)^2)(x +2)(x -3).

Multiply out all the factors using the FOIL (First Outer Inner Last) method to get the polynomial in the standard form. In the example, first multiply (x + 2)(x - 3) to get x^2 + 2x - 3x - 6 = x^2 - x - 6. Then multiply this with another factor (x + 1) to get (x^2 - x - 6)(x + 1) = x^3 +x^2 - x^2 - x - 6x - 6 = x^3 - 7x - 6. Finally, multiply this with the last factor (x + 1) to get (x^3 - 7x - 6)(x + 1) =x^4+x^3-7x^2-7x-6x-6 = x^4 + x^3 - 7x^2 - 13x - 6. This is the standard form of the polynomial.

zhuklara [117]3 years ago
6 0

Given the zeros of a polynomial, you can very easily write it -- first in its factored form and then in the standard form. Subtract the first zero from x and enclose it in parentheses. This is the first factor. For example if a polynomial has a zero that is -1, the corresponding factor is x - (-1) = x + 1.

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zloy xaker [14]
The formula to find the area of a circle is: π r squared. So, 4.5 π squared = about 63.62
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3 years ago
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What is the gcf of 14x^2 and 4xy
VikaD [51]
2x, would be the answer.
6 0
4 years ago
Write an equation of the line that passes through (-4,-1) and is perpendicular to the line y=4/3x+6
Sonja [21]

Answer:

y=-\dfrac{3}{4}x-4.

Step-by-step explanation:

If needed line is perpendicular to the line y=\dfrac{4}{3}x+6, then its slope satisfies condition

m\cdot \dfrac{4}{3}=-1\Rightarrow m=-\dfrac{3}{4}.

Then the equation of needed line will have look

y=-\dfrac{3}{4}x+b.

Since this line passes through the point (-4,-1), then

-1=-\dfrac{3}{4}\cdot (-4)+b,\\ \\-1=3+b,\\ \\b=-1-3=-4.

Hence, the equation is

y=-\dfrac{3}{4}x-4.

8 0
3 years ago
WORKED EXAMPLES
Doss [256]

Answer:

20

Step-by-step explanation:

Vertical angles are equal to each other

x = -3x + 80

x + 3x = 80

4x = 80 divide both sides by 4

x = 20

3 0
3 years ago
21.56 S-AQ) Healthy women aged 18 to 40 participated in a study of eating habits. Subjects were given bags of potato chips and b
IRISSAK [1]

Answer:

There is no effect of the good intentions i.e. to restrain their diet out of concern about their weight, have on their eating habits.

Step-by-step explanation:

The question is incomplete as some information is not provided, please refer below the remaining information of the question.

Here are the data on grams of potato chips consumed (note that the study report gave the standard error of the mean rather than the standard deviation):

Group          n     bar{x}         s

Unrestrained  9     63.83      24.72

Restrained  11     34      39.8

a. The standard error of the difference between sample means  ( ± 0.0001 )  is:

b. The critical value  ( ± 0.001 )  from the t distribution for confidence interval 80 % using the conservative degrees of freedom is:

c. Give a 80 % confidence interval   ( ± 0.01 )  that describes the effect of restraint:

Answer:

a) The standard error of the difference between sample means:

S E  =  √ s 2 1 /  n 1  +  s 2 2 /n 2

    =  √ s e 2 1 +  s e 2 2

    =  √ 24.72 2 +  39.8 2

    =  46.85

b) The degrees of freedom:

D f  =  n 1  + n 2  − 2

=  9  +  11  −  2

= 18

The confidence level  =  0.80

The significance level,  α  =  0.20

The critical value from the t distribution for confidence interval 80%:

t c r i t i c a l  =  t α / 2 ,  d f  =  t 0.10 , 18  =  ±  1.33

c) The 80% confidence interval:

( μ 1 − μ 2 ) = ( ¯ x 1 − ¯ x 2 )  ±  t ⋅ S E

= ( 63.83 − 34 ) ±  1.33 × 46.85  

= 29.83 ± 62.31

− 32.48 < ( μ 1 − μ 2 ) <  92.14

As the interval contains the zero. So, it can be concluded that there is no effect of the good intentions i.e. to restrain their diet out of concern about their weight, have on their eating habits.

5 0
4 years ago
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