Answer:Find the distance between the parallel lines m and n whose equations are y = x + 4 and y = x - 6, respectively.
There are several ways to do this...here's one
Let (0, 4) be a point on the first line
Then.......a line with a negative reciprocal slope going through this point will have the equation :
y = -x + 4........so......we can find the intersection of this line with y = x - 6....set both equations equal
-x + 4 = x - 6 add x, 6 to both sides
10 = 2x divide both sides by 2
5 = x
So...using -x + 4, the y value at intersection = -1.......
So...we just need to find the distance from (0,4) to ( 5, -1) =
√[ (5)^2 + (4 + 1)^2 ] = 5√2 ≈ 7.07 units
Here's a pic....AB is the distance with A = (0,4) and B = (5, -1)
Step-by-step explanation:
you need to find to find the value of x and y.
2x>(-15-5y)
x>(-15-5y)/2
now put this in to other equation and solve for y and then put the y value in and find x.
Here is the answer. I’m not so sure if my answer is correct about which side should it be shaded and whether it’s a dotted or solid line, but I hope you will get some sort of idea .
Answer: Upper right corner
You divide every value in the table over 120 as 120 is the grand total
So we have 28/120 = 0.23 in row 1, column 1
Then we have 14/120 = 0.12 in row 1, column 2
etc etc
