Triangles: 2(1/2)*8*6=
Left side: 6*10 =
Right side: 8*10 =
Back side: 10*10 =
48 + 60 + 80 + 100 = 288cm^2
I'm assuming that the line is JKL in order of the points from left to right.
JK + KL = JL
(17-x) + (2x-7) = JL
Simplify.
10-x = JL
Answer:
A
Step-by-step explanation:
the height a creates with half of the baseline (5) and a leg (10) a right-angled triangle, and we can use Pythagoras to calculate a.
c² = a² + b²
c being the Hypotenuse (the side opposite of the 90° angle, so in our case the 10 side).
10² = a² + 5²
100 = a² + 25
75 = a²
a = sqrt(75) = sqrt(3×25) = 5×sqrt(3)
I think the answer is 2 13/20
Or, in decimals: 1.3
