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shutvik [7]
3 years ago
10

This is my work so far but I believe I’m doing it wrong. I have to, “Solve for X in the diagram”. Need help ASAP

Mathematics
2 answers:
Lelu [443]3 years ago
7 0
You almost got it right

Supplementary angles, angles whose sum 180°
∠UTV + 90° = 180°
∠UTV = 180° - 90°
∠UTV = 90°

Exterior angle of a triangle, an angle formed from the extension of a side on the triangle and equals to the sum of the opposite interior angles
∠UVS = ∠UTV + ∠TUV
x + 8 = 90 + 64
x + 8 = 154
x + 8 - 8 = 154 - 8
x = 146

The value of x is 146
Lorico [155]3 years ago
3 0
X + 8 = 60 + 94.

This is geometrically correct, now you must solve the algebra portion.

60 + 94 is just 154, which means x + 8 = 154.

What number + 8 = 154? It must be 146.
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The answer choices are 11 1 2.48 6
Fudgin [204]

Answer:

The ball reached its maximum height of (11\ yards) in (1\ second).

Step-by-step explanation:

This question is essentially asking one to find the vertex of the parabola formed by the given equation. One could plot the equation, but it would be far more efficient to complete the square. Completing the square of an equation is a process by which a person converts the equation of a parabola from standard form to vertex form.

The first step in completing the square is to group the quadratic and linear term:

h(t)=-5t^2 + 10t + 6\\\\h(t) = (-5t^2 + 10t) + 6

Now factor out the coefficient of the quadratic term:

h(t)=-5(t^2 -2t) + 6

After doing so, add a constant such that the terms inside the parenthesis form a perfect square, don't forget to balance the equation by adding the inverse of the added constant term:

h(t) = -5(t^2 -2t) + 6\\\\h(t) = -5(t^2 -2t + 1 -1 ) + 6

Now take the balancing term out of the parenthesis:

\\\\h(t)=-5(t^2 -2t + 1) + 6 + ((-1)(-5))

Simplify:

h(t) = -5(t^2 -2t + 1) + 6 + 5\\\\h(t) = -5(t-1)^2 + 11

The x-coordinate of the vertex of the parabola is equal to the additive inverse of the numerical part of the quadratic term. The y-coordinate of the vertex is the constant term outside of the parenthesis. Thus, the vertex of the parabola is:

(1, 11)

8 0
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