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soldier1979 [14.2K]
3 years ago
8

Write a quadratic formula vertex ( 2,3 ) point ( 1,-7 )

Mathematics
1 answer:
jonny [76]3 years ago
5 0

The vertex formula:

f(x)=a(x-h)^2+k

(h, k) - vertex

We have vertex (2, 3). Therefore:

f(x)=a(x-2)^2+3

We know that the parabola passes (1, -7).

Put the coordinates of this point into the function equation

x = 1, f(x) = -7

a(1-2)^2+3=-7\ \ \ \ |-3\\\\a(-1)^2=-10\to a=-10

Therefore we have:

f(x)=-10(x-2)^2+3

Use (a-b)^2=a^2-2ab+b^2

f(x)=-10(x^2-2x(2)+2^2)+3=-10(x^2-4x+4)+3\\\\=-10x^2+40x-40+3=-10x^2+40x-37

<h3>Answer: f(x) = -10x² + 40x - 37</h3>
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