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Artist 52 [7]
3 years ago
11

-|-5| Is the answer greater than, less than, or equal to -5

Mathematics
1 answer:
ehidna [41]3 years ago
3 0

Answer:

equal to

Step-by-step explanation:


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Find the solution to the following system using substitution. y = - 4 + 9 y = 3x - 5
lbvjy [14]

Answer:

1/2, 11/6

Step-by-step explanation:

y=-4+9y

9y-y=4

8y=4

y=1/2

3x-5=1/2

3x=5+1/2=11/2

x=11/6

6 0
2 years ago
PLS HELP!! need the answer asap
Tomtit [17]

Answer:

its D

Step-by-step explanation:

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180-65

4 0
3 years ago
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Definition of a random sample
Gnesinka [82]

Answer:

Step-by-step explanation:

In statistics, a simple random sample is a subset of individuals (a sample) chosen from a larger set (a population). Each individual is chosen randomly and entirely by chance, such that each individual has the same probability of being chosen at any stage during the sampling process, and each subset of k individuals has the same probability of being chosen for the sample as any other subset of k.

7 0
3 years ago
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Use​ l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove
steposvetlana [31]

Answer:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}

Step-by-step explanation:

The limit is:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}

by replacing, and applying repeatedly you obtain:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}

hence, the limit of the function is -1/14

8 0
3 years ago
The average of p, q, and r is 40. The average of a, b, c, and d is 5. What is the average of a, b, c, d, p, q, and r?
Pachacha [2.7K]

Answer:

20

Step-by-step explanation:

Average = sum of numbers divided by number of numbers

sum of p q and r: 40*3=120

sum of a b c and d: 5*4=20

sum of a b c d p q r: 120+20=140

average of a b c d p q r: 140/7, or 20

3 0
3 years ago
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