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3 years ago

15

Oleg ran 8.8 miles in 1 hour and 20 min. Assuming he continues at a constant rate ,how long will it take him to run any number o

f miles?

1 answer:

hammer [34]3 years ago

5 0

Calculate his running rate in miles per hour:-

1 hour and 20 minutes = 4/3 hours.

His mph = 8.8 / 4/3 = 8.8 * 3/4 = 6.6 mph

Time = distance / rate

Time to run any number of miles ( n miles) = n / 6.6

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Explain how you can use base ten blocks to find 1.54+ 2.37

solong [7]

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*First column to your left - ones column (1)
*Column just after decimal place, in the middle - tenths column (1/10)
*Column to the far right - hundredths column (1/100)

The only numbers that can go in these columns are 0-9.

-------------

1.54 + 2.37

= (1 + 5/10 + 4/100) + (2 + 3/10 + 7/100)

= 1 + 5/10 + 4/100 + 2 + 3/10 + 7/100

= 3 + 8/10 + 11/100

= 3 + 8/10 + (10/100 + 1/100)

= 3 + 8/10 + (1/10 + 1/100)

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3 years ago

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Javier rode his bike for a total of 40 minutes. The number of minutes he rode after lunch is 4 times the number of minutes he ro

Greeley [361]

Javier rode his bike for a total of 40 minutes.

Let x be the minutes Javier ride after lunch

Let y be the minutes Javier ride before lunch

The number of minutes he rode after lunch is 4 times the number of minutes he rode before lunch

x = 4 y

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3 years ago

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Mazyrski [523]

Answer:

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The probability of at least 1 failure in a 24-hour day is $P(X\geq 1 )\approx 0.3508$

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

$P(X)=\frac{e^{-\mu}\mu^x}{x!}$

Let X be the number of failures of a testing instrument.

We know that the mean $\mu = 0.018$ failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is $\mu=8\cdot 0.018=0.144$

$P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659$

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is $\mu=24\cdot 0.018=0.432$

$P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508$

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Sedbober [7]

Answer:

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Step-by-step explanation:

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