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raketka [301]
3 years ago
13

PLEASE HELP ME :(

Mathematics
1 answer:
sp2606 [1]3 years ago
8 0

Hi army! I found the answer!

Answer:

F. An 18-month loan with an annual simple interest rate of 4.75%

Step-by-step explanation:

I just used a credit card payoff calculator to solve this problem. You can use that calculator to solve other problems like this too!

<em><u>Also, stream BTS Film Out for clear skin and good grades ;)</u></em>

Have a great day!

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PLZ HELP!
Shtirlitz [24]

Answer:

vertex and x= -b/2a = 0

second point, when x=1, y=3

third point the mirror of the second point over the vertex

Step-by-step explanation:

Do as described

8 0
2 years ago
Tabitha and her mother went to the pet store. Her mother told her she could either choose a cat, dog, or fish, and either get a
FinnZ [79.3K]
For the pet the fraction is 2/3 because there is a fish,cat and a dog only cats and dogs have 4 legs and the fraction for the toy or the book is 1/2 because there are 2 objects and she can only get 1
7 0
3 years ago
How do I work this out I need full answer im lost​
taurus [48]

Answer:

7x = 35cm ; 2x = 10cm

Step-by-step explanation:

7x and 2x are the lengths

7x+2x=45

Then you take 7 + 2 = 9

so is gonna be 9x = 45

then you divide both side with 9

so is gonna be x = 5

Then you take 5 multiply 7 : 2

so 7 x 5 = 35cm

2 x 5 = 10cm

7 0
2 years ago
Help please tell me what the answer is ASAP
Amiraneli [1.4K]

Answer:

The approximated length of EF is 2.2 units ⇒ A

Step-by-step explanation:

<em>The tangent ratio in the right triangle is the ratio between the opposite side to the adjacent side of one of the acute angle in the triangle</em>

In the given figure

∵ The triangle DFE has a right angle F

∵ The opposite side to angle D is EF

∵ The adjacent side to angle D is DF

→ By using the tangent ratio above

∴ tan(∠D) = \frac{EF}{DF}

∵ DF = 6 units

∵ m∠D = 20°

→ Substitute then in the ratio above

∴ tan(20°) = \frac{EF}{6}

→ Multiply both sides by 6

∴ 6 tan(20°) = EF

∴ 2.183821406 = EF

→ Approximate it to the nearest tenth

∴ 2.2 = EF

∴ The approximated length of EF is 2.2 units

7 0
3 years ago
A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit
Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = -  (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] =  20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0
3 years ago
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