Not really sure what you are looking for, but this is how to solve equations such as these.
Let:
x = number of pounds of granola
y = numer of pounds of walnuts
The equation he can use to compute the total cost would be:
$2.00x + $6.00y = $12.00
We know that he bought 3 pounds of granola, so we plug in that for the x value:
$2.00(3) + $6.00y = $12.00
$6.00 + $6.00y = $12.00
To isolate the unknown value which is y, we first need to subtract $6.00 from both sides of the equation:
$6.00 + $6.00y - $6.00 = $12.00 - $6.00
$6.00y = $6.00
Then we divide both sides by $6.00:
$6.00y/$6.00 = $6.00/$6.00
y = 1
So the number of bags of walnuts he can buy is 1 bag.
if y=367
then you need to figure out this:
367=5x+287
so remove 287 from 367
367-287=80
Then divide by 5
80/5=16
so, x=16
9n + 4n^2 because you combine like terms. combine the two n's that are not squared then add the two n^2 together to get 9n+4n^2
Answer:
20*5=100
So it would be 13*5=65
Step-by-step explanation:
Answer:
Step-by-step explanation:
we know that
The simple interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods
in this problem we have
substitute in the formula above and solve for t
![t=[(645/600)-1]/0.025=3\ years](https://tex.z-dn.net/?f=t%3D%5B%28645%2F600%29-1%5D%2F0.025%3D3%5C%20years)
