(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when 
and 
, and because the velocity function is continuous, you need only check the sign of 
for values on the intervals (0, 3) and (3, 6).
We have, for instance 
and 
, which means the particle is moving the positive direction for 
, or the interval (3, 6).
(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:
which follows from the definition of absolute value. In particular, if 
is negative, then 
.
The total distance traveled is then 4 ft.
(g) Acceleration is the rate of change of velocity, so 
is the derivative of :
Compute the acceleration at 
seconds:
(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)
Answer:
6:05
Step-by-step explanation:
5:20+40= 6:00
6:00+5= 6:05
Area of rectangle b=1/2 area of rectangle a=40/2=20 cm²
Length=8 cm
Width of rectangle b=20/8 =2.5 cm
To take 16.5 units from zero to the right on a number line.
Answer:
A: It has no solution
Step-by-step explanation:
1. 3/4z - 1/4z + 3 = 2/4z + 5
2. 2/4z +3 = 2/4z + 5
3. 3 = 5 (No solution because 3 can never be equal to 5)
