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4 years ago

T^3(8 + 9t) - (t2 + 4) (2 – 3t)

Mathematics

1 answer:

mezya [45]4 years ago

4 0

Answer: a & b

Step-by-step explanation:

t³(8 + 9t) - (t² + 4)(2 - 3t)

= 8t³ + 9t⁴ - (2t² - 3t³ + 8 - 12t)

= 8t³ + 9t⁴ - 2t² + 3t³ - 8 + 12t

= 9t⁴ + 11t³ - 2t² + 12t - 8

a) The simplified expression is a polynomial. TRUE

b) The simplified expression has a constant term. TRUE

c) The simplified expression is cubic. False - it is degree 4

d) The simplified expression has four terms. False - it has 5 terms

e) The simplified expression is a trinomial False - it has 5 terms

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I have to find measurement of angle AED

Andrei [34K]

Answer:

$m\angle AED=116\degree$

Step-by-step explanation:

By intersecting chords theorem:

$m\angle AED=\frac{1}{2} (92+140)\degree$

$m\angle AED=\frac{1}{2} \times 232\degree$

$m\angle AED=116\degree$

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3 years ago

Alyssa buys a carton of 12 eggs for $1.80. Which is the cost per egg?

sesenic [268]

Answer:

B is the answer

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Step-by-step explanation:

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3 years ago

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A circle with a radius of 10 inches is placed inside a square with a side length of 20 inches. Find the probability that a dart

melamori03 [73]

Answer:

The correct answer is last option 78.5%

Step-by-step explanation:

Points to remember

Area of circle = πr²

Where r is the radius of circle

Area of square = a²

Where 'a' is the side length of square

To find the area of circle

Here r = 10 cinches

Area = πr²

= 3.14 * 10²

= 3.14 * 100 = 314

To find the area of square

Here a = 20 inches

Area = a²

= 20²

= 400

To find the probability percentage

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= (314/400)*100

78.5 %

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3 years ago

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What phrases describes the expression of 16-y

Jlenok [28]

What phrases describes the expression of 16-y

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Hope this helps~

6 0

3 years ago

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}$

$\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}$

$\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}$

$\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}$

$\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}$

$\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}$

$\mathsf{\implies \dfrac{5 - 1}{5 + 1}}$

$\mathsf{\implies \dfrac{4}{6}}$

$\mathsf{\implies \dfrac{2}{3}}$

Hence, option (a) 2/3 is your correct answer.

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3 years ago