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Elan Coil [88]
3 years ago
9

When is a variable solved for?

Mathematics
1 answer:
Margarita [4]3 years ago
4 0

Answer:Let's say you're being asked to solve for y and the problem looks like this: 16x+4y=20. Basically what's being asked here is to get all the numbers on the other side of the equal sign so that y is by itself, i.e. y=(all the other things you've put on the other side of the equal sign).

Step-by-step explanation:

Different ways to solve equations. We have 4 ways of solving one-step equations: Adding, Substracting, multiplication and division. If we add the same number to both sides of an equation, both sides will remain equal.

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Please help me on this big question
STatiana [176]

Answer:

1.E, F

2. ↔ AE

3. X

4.Y

Step-by-step explanation:

4 0
3 years ago
S $1,595 deposit for 10 years at a simple interest rate of 8%
o-na [289]

Answer:

$2,871.00

Step-by-step explanation:

Calculation:

First, converting R percent to r a decimal

r = R/100 = 8%/100 = 0.08 per year.

Solving our equation:

A = 1595(1 + (0.08 × 10)) = 2871

A = $2,871.00

The total amount accrued, principal plus interest, from simple interest on a principal of $1,595.00 at a rate of 8% per year for 10 years is $2,871.00.

6 0
3 years ago
Write the sentence as an inequality.<br> A number b divided by -14 is less than -25.
grin007 [14]

Answer:

b ÷ -14 < -25

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which function represents the graph? Y=-cos(x) y=-sin(x)y=cos(x)y=sin(x)
pishuonlain [190]

Answer:

y=cos(x)

Step-by-step explanation:

since the period doesnt start at (0,0) it is cos.

the wave also starts at a positive (0,1) so it is positive

6 0
3 years ago
The standard form of a quadratic equation is given as y=ax^2+bx+c and vertex form is given as y=a(x−h)^2+k. Write a formula that
Tju [1.3M]

Answers:

h = -\frac{b}{2a}\\\\k = \frac{-b^2+4ac}{4a}\\\\

where 'a' cannot be zero.

=========================================================

Explanation:

The vertex is (h,k)

The x coordinate of the vertex is h which is found through this formula

x = -\frac{b}{2a}

For example, if we had the quadratic y = 3x^2-6x+5, then we'll plug in a = 3 and b = -6 to get: h = -\frac{b}{2a} = -\frac{-6}{2*3} = 1

------------

To find the value of k, we plug that h value into the original standard form of the quadratic and simplify.

y = ax^2+bx+c\\\\k = ah^2+bh+c\\\\k = a\left(\frac{-b}{2a}\right)^2+b\left(\frac{-b}{2a}\right)+c\\\\k = a*\frac{b^2}{4a^2}+\frac{-b^2}{2a}+c\\\\k = \frac{b^2}{4a}+\frac{-b^2}{2a}+c\\\\

k = \frac{b^2}{4a}+\frac{-b^2}{2a}*\frac{2}{2}+c*\frac{4a}{4a}\\\\k = \frac{b^2}{4a}+\frac{-2b^2}{4a}+\frac{4ac}{4a}\\\\k = \frac{b^2-2b^2+4ac}{4a}\\\\k = \frac{-b^2+4ac}{4a}\\\\

It's interesting how we end up with the numerator of -b^2+4ac which is similar to b^2-4ac found under the square root in the quadratic formula. There are other ways to express that formula above. We need a \ne 0 to avoid dividing by zero. The values of b and c are allowed to be zero.

7 0
3 years ago
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