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almond37 [142]
3 years ago
14

A Frisbee has a diameter which measures 10.2 inches. Consider the greatest possible error allowed for the measurement and calcul

ate the minimum circumference of the Frisbee to the nearest tenth.
Mathematics
2 answers:
Marina CMI [18]3 years ago
7 0

Answer:

31.9 inches.

Step-by-step explanation:

A Frisbee has a diameter which measures 10.2 inches.

The greatest possible error is 0.05 because the measurement was made to the nearest tenth.

So, the diameter is = 10.2-0.05 = 10.15

radius = \frac{10.15}{2} = 5.075

Circumference is given as: 2\pi r

= 2\times3.14\times5.075

= 31.87 rounding to nearest tenth as 31.9 inches.

The minimum circumference of the Frisbee to the nearest tenth is 31.9 inches.

Anestetic [448]3 years ago
6 0
In the dimension of the frisbee given to be 10.2 inches in diameter, there are three significant figures. All, from 1, 0 and 2. Since these values are all significant, the last digit determines the greatest possible error allowed that is only in the tenths digit. The circumference of the frisbee is calculated through the equation,
                                            C = πD
Substituting,
                                            C = π(10.2 in) ≈ 32.0 in

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densk [106]

Answer:

Step-by-step explanation:

%change=100(final-initial)/(initial)

%change=100(40-32)/32

%change=25%

3 0
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You would need 31 Vans for everyone to be transported.
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The shaded sector above covers 1/3 of the circle. If the radius of the circle above is 3 cm, what is the area of the sector in t
Mekhanik [1.2K]

Given:

The shaded sector above covers \dfrac{1}{3} of the circle.

Radius of the circle = 3 cm

To find:

The area of the sector in terms of π.

Solution:

The area of a circle is

A=\pi r^2

Substituting r=3, we get

A=\pi (3)^2

A=9\pi

It is given that the shaded sector above covers \dfrac{1}{3} of the circle.

The area of shaded sector =\dfrac{1}{3}A

                                             =\dfrac{1}{3}(9\pi)

                                             =3\pi

Therefore, the area of shaded sector is 3π sq. cm.

5 0
3 years ago
Please help asap :( This is my "Final grade" My Teacher wants a full explanation included ! on how i got the answer. )
Mrac [35]

If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)

The total volume of the ball will be;

= Total volume - Volume of hollow part

= 4/3πr³ - 4/3πr³

= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³

= 4 × 3.14 × 9 - 4/3 × 3.14 × 8

= 113.04 - 33.52

= 79.52

If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;

= 79.52 × 3.25

= 258.44 g

Now, if there are 8 spheres in one box, the weight if box will be;

= 258.44 × 8

= 2,067.52 g

_____________________________

Ahh! Finally done with this, if you have any doubt just do ask me :)

3 0
3 years ago
Find the angles marked with the letters​
arsen [322]

Answer:

C = 64   B = 55

Step-by-step explanation:

Might be wrong but give it a try

7 0
3 years ago
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