For sake of convenience, reverse the series, then it would be:
21,19,17.....7
a=21, d = -2,
s(4) = 4/2 (21+15)
s(4)=2(36)
s(4) = 72
Answer:
x=2
Step-by-step explanation:
-2x+4=6x-12 Add 2x to both sides.
<u>+2x +2x</u>
4=8x-12 Add 12 to both sides.
<u>+12 +12</u>
16=8x Divide by 8 on both sides.
<u>/8 /8</u>
2=x
Hope this helps you out and have a great day (～^▽^)～
Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}
Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number
Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}
Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}
Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}
The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer
Note: It is similar to how 999 is the largest 3-digit base 10 integer
simplify the expression (4g^10)^4
<h2><em><u>
A.256g^40</u></em></h2>
B. 4g^40
C.256g^14
