Answer:
x = 4 ±9i
Step-by-step explanation:
x^2 - 8x + 97 = 0
Complete the square by subtracting 97 from each side
x^2 - 8x =- 97
Take the coefficient of x
-8 and divide by 2
-8/2 = -4
Then square it
(-4)^2 = 16
Add it to each side
x^2 - 8x + 16 = -97+16
(x-4)^2 = -81
Take the square root of each side
x-4 = ±sqrt(-81)
x-4 = ±9i
Add 4 to each side
x = 4 ±9i
Answer:
the answer is 45/8 very direct
Hello,
Answer D -3<x<27
Indeed:
1)
if x-12≥0 then x≥12 and
|x-12|=x-12x-12<15 → x<27
so 12≤x<27
2) if x-12<0 then
x<12 and|x-12|=-(x-12)<15
-x+12<15-x<3 → x>-3
So -3<x<12
Thus -3<x<12 U 12≤x<27 ⇔ -3<x<27
PROBLEM ONE
•
Solving for x in 2x + 5y > -1.
•
Step 1 ) Subtract 5y from both sides.
2x + 5y > -1
2x + 5y - 5y > -1 - 5y
2x > -1 - 5y
Step 2 ) Divide both sides by 2.
2x > -1 - 5y


So, the solution for x in 2x + 5y > -1 is...

•
Solving for y in 2x + 5y > -1.
•
Step 1 ) Subtract 2x from both sides.
2x + 5y > -1
2x - 2x + 5y > -1 - 2x
5y > -1 - 1x
Step 2 ) Divide both sides by 5.
5y > -1 - 1x


So, the solution for y in 2x + 5y > -1 is...

•
PROBLEM TWO
•
Solving for x in 4x - 3 < -3.
•
Step 1 ) Subtract 3 from both sides.
4x - 3 < -3
4x -3 - 3 < -3 - 3
4x < 0
Step 2 ) Divide both sides by x.
4x < 0

x < 0
So, the solution for x in 4x - 3 < -3 is...
x < 0
•
•
- <em>Marlon Nunez</em>
Answer:
the answer above me don't click it that's kinda sus sooo
Step-by-step explanation:
The box in the shape of a rectangular prism it measures 15 in. long, 11 in. wide, and 24 in. tall A so in B in.2 © 789 in.2 1,578 in.2