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makkiz [27]
3 years ago
5

Can Someone Please Help me with this?​

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

PA = 30.81

Step-by-step explanation:

Use the Pythagorean Theorem

18^2+25^2=949

Take the Square Root

\sqrt{949} = 30.805 = 30.81

PA = 30.81

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Primos número entre 1 e 20
jeka57 [31]

Prime 1-20 = {2,3,5,7}

7 0
3 years ago
Exclude leap years from the following calculations. ​(a) Compute the probability that a randomly selected person does not have a
Scrat [10]

Answer:

a) 99.73% probability that a randomly selected person does not have a birthday on March 14.

b) 96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

c) 98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

d) 92.33% probability that a randomly selected person was not born in February.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A non-leap year has 365 days.

​(a) Compute the probability that a randomly selected person does not have a birthday on March 14.

There are 365-1 = 364 days that are not March 14. So

364/365 = 0.9973

99.73% probability that a randomly selected person does not have a birthday on March 14.

​(b) Compute the probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

There are 12 months, so there are 12 2nds of a month.

So

(365-12)/365 = 0.9671

96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

​(c) Compute the probability that a randomly selected person does not have a birthday on the 31 st day of a month.

The following months have 31 days: January, March, May, July, August, October, December.

So there are 7 31st days of a month during a year.

Then

(365-7)/365 = 0.9808

98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

(d) Compute the probability that a randomly selected person was not born in February.

During a non-leap year, February has 28 days. So

(365-28)/365 = 0.9233

92.33% probability that a randomly selected person was not born in February.

6 0
3 years ago
The sum of 6 even integers is 130 what is the 2nd number in the sequence
castortr0y [4]

Answer:

The 2nd number in the sequence is 2\left(\frac{100}{12}\right)+2

Step-by-step explanation:

Let the six even numbers be 2x,2x+2,2x+4,2x+6,2x+8,2x+10

We are given that The sum of 6 even integers is 130.

So,2x+2x+2+2x+4+2x+6+2x+8+2x+10=130

12x+30=130

12x=100

x=\frac{100}{12}

So,the 2nd number in the sequence is 2\left(\frac{100}{12}\right)+2

6 0
4 years ago
Read 2 more answers
Your friend is going to buy a used car. The one he is considering costs $4000 and will lose value at a rate of 13% per year. How
guapka [62]

13% of $4000 is $520
If the $4000 car loses value at a rate of 13% each year for 3 years
$520 x 3 = $1560
Subtract this amount from $4000
$4000 - $1560 = $2440

<u>Answer: In 3 years, the used car will be worth $2440 in 3 years</u>

6 0
3 years ago
If 60% of a KNOWN NUMBER is 180, what is the 40% of that UNKNOWN NUMBER?
Lana71 [14]

Step-by-step explanation:

I think you mean you want to find out 40% of a number,, when 60% of it is 180, so I'll answer that:

60% = 180

÷6

10% = 30

x4

40% = 120

(if you want to find 100%, multiply 30 by 10)

Hopefully this helps :)

4 0
3 years ago
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