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Hitman42 [59]
3 years ago
9

2.8151 rounded to the nearest thousandth

Mathematics
1 answer:
zaharov [31]3 years ago
5 0

Answer:

2.815

Step-by-step explanation:

2.8151 rounds DOWN due to the 1 being under 5.

if the last digit is 5 or above, it rounds UP.

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Assume that two chords in a given circle are congruent. Which of the following must also be true?
o-na [289]

Answer:

If the two chords are congruent, then they must be equidistant from the centre of the circle. 

Ans: D

5 0
3 years ago
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Answer:

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4 0
3 years ago
2. Solve the<br> triangle.<br> a = 12, b = 22, C = 95°
djyliett [7]

this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?

Answer:

Reasons:

The given parameters are;

Distance between the two stations = 146 miles

Location of the weather balloon from the Western station = N35°E

Location of the weather balloon from the Eastern station = N23°E

The location of the station = On the equator

Required:

The distance of the balloon from the Western station

Solution:

- The angle formed between the horizontal, and the line from the Western station

to the balloon = 90° - 35° = 55°

- The angle formed between the horizontal, and the line from the Eastern station

to the balloon = 90° + 23° = 113°

The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°

By sine rule,

Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)

Therefore;

Distance from balloon to western station = 146/sin(12 dg) x sin(113 dg) ~ 646.4

Step-by-step explanation:

7 0
2 years ago
Prove that <br><img src="https://tex.z-dn.net/?f=4cot45%20%5E%7B2%7D%20%20-%203tan%20%5E%7B2%7D%2060%20%2B%202sec%20%5E%7B2%7D60
sesenic [268]

Answer:

4 \cot {}^{2} (45)  - 3 \tan {}^{2} (60)  + 2 \sec {}^{2} (60)  = 3 \\

LHS = 4 \cot {}^{2} (45)  - 3 \tan {}^{2} (60)  + 2 \sec {}^{2} (60)  \\

let us first take a look at the values of the trigonometric ratios given in the question so that we get quite clear about what is to be done.

here ,

\cot(45)  = 1 \\  \\  \tan(60)  =  \sqrt{3}  \\  \\  \sec(60)  = 2

now ,

we just have to plug in the values considering certain other things given in the question and we're done!

so let's start ~

4(1) {}^{2}  - 3( \sqrt{3} ) {}^{2}  + 2(2) {}^{2}  \\ \\ \dashrightarrow \: 4(1) - 3(3) + 2(4) \\ \\ \dashrightarrow \: 4 - 9 + 8 \\\\ \dashrightarrow \: 12 - 9 \\ \\\dashrightarrow \: 3 = RHS

hence , proved ~

hope helpful :D

7 0
2 years ago
3p+6<br> Which phrase represents the algebraic expression 7p-9?
Tresset [83]

Answer:

The answer is the sum of three times a number and six, divided by the difference of seven times the number and nine

Step-by-step explanation:

3p = three x a number

7p = seven x a number

3p+6 = sum of three x a number plus six

7p-9 = difference of seven x the number minus nine

(3p+6)/(7p-9) = sum of three times x number plus six, divided by the difference of seven x the number - nine

6 0
2 years ago
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