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3 years ago

Are my answer correct

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

5 0

Yep, this looks good!

Elena-2011 [213]3 years ago

3 0

Isnt the answer for qn 3 c?

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In the Itty Bitty High School, there are 85 students. There are 27 students who take French, 51 who take Geometry and 38 who tak

andrew-mc [135]

Answer:

58 students

Step-by-step explanation:

Given

$Total = 85$

$French = 27$

$Geometry = 51$

$History = 38$

$None = 5$

$All = 2$

Required

Students that take only 1 subjects

The attached image illustrates the question.

For French only (x), we have:

$x + 7 -2+10-2+2=27$

$x + 15=27$

Collect like terms

$x =- 15+27$

$x =12$

For Geometry only (y), we have:

$y+10-2+15-2+2=51$

$y+23=51$

Collect like terms

$y=-23+51$

$y=28$

For History only (z), we have:

$z +15-2+7-2+2=38$

$z +20=38$

Collect like terms

$z =-20+38$

$z =18$

Students with one subject is then calculated as:

$1\ subject = x+y+z$

$1\ subject = 12 + 28 + 18$

$1\ subject = 58$

5 0

3 years ago

Find dy/dx by implicit differentiation for ysin(y) = xcos(x)

tatyana61 [14]

Answer:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

Step-by-step explanation:

So we have:

$y\sin(y)=x\cos(x)$

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[y\sin(y)]$

We can use the product rule:

$(uv)'=u'v+uv'$

So, our derivative is:

$=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]$

We must implicitly differentiate for y. This gives us:

$=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]$

For the sin(y), we need to use the chain rule:

$u(v(x))'=u'(v(x))\cdot v'(x)$

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

$=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})$

Simplify:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}$

And we are done for the right.

Right Side:

We have:

$\frac{d}{dx}[x\cos(x)]$

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

$=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]$

Differentiate:

$=\cos(x)-x\sin(x)$

So, our entire equation is:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)$

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

$\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)$

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

And we're done!

5 0

3 years ago

Plz help I need your help plz help me plz I swear I need your help plz help me plz I’m begging you on my 2 knees plz help me

REY [17]

Answer:

The correct answer is B

Step-by-step explanation:

First, the question said that the shoes were $15 less than double the price of his pants. In algebra 2p would mean 2 multiplied by p so we know that C and D are wrong. Now $15 less than 2p would mean you have to subtract by 15, so now we have 2p-15. Since we haven't added in the amount of money the pair of pants cost, we have to use addition to add it in, and that adds to the equation making the equation 2p - 15 + p. So, the answer is B.

6 0

3 years ago

A boy is Y years old. His father is twice as old as he is. The sum of their ages is 63. How old is the boy?

Arturiano [62]

Hi!
Divide 63 by 3. You will get 21. That is the boys age. His father’s age is 42. When combined their age is 63.

3 0

3 years ago

Read 2 more answers

Devin's bank charges $1.75 for nonbank ATM withdrawals and $0.30 for each debit card transaction. Last month, Devin paid $8.25 i

nikdorinn [45]

Answer:

10 times

Step-by-step explanation:

3 nonbank atm withdrawals costs 5.25 and the total is 8.25 meaning the remaining must add up to 3. And if you multiply .3 by 10 it gives you 3

8 0

3 years ago