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3 years ago

Are my answer correct

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

5 0

Yep, this looks good!

Elena-2011 [213]3 years ago

3 0

Isnt the answer for qn 3 c?

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from a group of 25 men,12 were to be given gifts.What is the probability of choosing a man who did not a gift

nikklg [1K]

Answer: 13/25

Explanation:

There are 25 men in total
12 were to be given gifts

Find the probability of choosing a man who did not receive a gift:

P = 25/25 - 12/25 = 13/25

6 0

4 years ago

Read 2 more answers

Suppose that the times required for a cable company to fix cable problems in its customers’ homes are uniformly distributed betw

vampirchik [111]

Answer:

a) 60% probability that a randomly selected cable repair visit will take at least 50 minutes

b) 60% probability that a randomly selected cable repair visit will take at most 55 minutes.

c) The expected length of the repair visit is 52.5 minutes.

d) The standard deviation is 7.22 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

For this problem, we have that:

Uniformly distributed between 40 and 65 minutes, so $a = 40, b = 65$

(a) What is the probability that a randomly selected cable repair visit will take at least 50 minutes?

Either it takes less than 50 minutes, or it takes at least 50 minutes. The sum of the probabilities of these events is decimal 1. So

$P(X < 50) + P(X \geq 50) = 1$

The intervals can be open or closed, so

$P(X < 50) = P(X \leq 50)$

We have that

$P(X \geq 50) = 1 - P(X < 50)$

$P(X < x) = \frac{50 - 40}{65 - 40} = 0.4$

$P(X \geq 50) = 1 - P(X < 50) = 1 - 0.4 = 0.6$

60% probability that a randomly selected cable repair visit will take at least 50 minutes

(b) What is the probability that a randomly selected cable repair visit will take at most 55 minutes?

This is $P(X \leq 55)$

$P(X \leq 55) = \frac{55 - 40}{65 - 40} = 0.6$

60% probability that a randomly selected cable repair visit will take at most 55 minutes.

(c) What is the expected length of the repair visit?

The mean of the uniform distribution is:

$M = \frac{a+b}{2}$

$M = \frac{40+65}{2} = 52.5$

The expected length of the repair visit is 52.5 minutes.

(d) What is the standard deviation?

The standard deviation of the uniform distribution is

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

$S = \sqrt{\frac{(65-40)^{2}}{12}}$

$S = 7.22$

The standard deviation is 7.22 minutes.

5 0

3 years ago

Need help? Answer question it’s simple.

Oxana [17]

Answer:

118

Step-by-step explanation:

Cause the degree is 180 so 62+118+ 180

5 0

3 years ago

8 divided by 5thirds

Igoryamba

Answer:

if you mean 8 devided by 5/3 then the answer is 4.8 :)

Step-by-step explanation:

7 0

3 years ago

I have a question on a homework problem. Select the function that represents an arithmetic sequence.

Fynjy0 [20]

7 ig because I mean if you take a look at the problem

4 0

3 years ago