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s344n2d4d5 [400]
3 years ago
11

Hal has just purchased a small rectangular fish tank that holds 970.2 milliliters of water. The tank has a length of 14 cm and a

height of 11 cm. What is the width of the fish tank? (1 milliliter is equal to 1 cubic centimeter)
Mathematics
1 answer:
kodGreya [7K]3 years ago
4 0

Answer:

the width is 6.3

Step-by-step explanation:

11 x 14 = 154

970.2 divided by 154 =6.3

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What is the answer to<br> -12 + 7 = __
bixtya [17]

Answer:

-5

Step-by-step explanation:

an easy way to do it is to flip it so its 7-12 or you can do 12-7 and you get 5 then just add a - sign but thats my way and its weird lol

6 0
4 years ago
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Solve<br>4(2x - 3) = 6x + 2​
vaieri [72.5K]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

4(2x - 3) = 6x + 2

Expand it:

8x - 12 = 6x + 2

+ 12 to both sides

8x = 6x + 14

- 6x from both sides

2x = 14

Divide both sides by  2:

x = 7

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4 0
3 years ago
I don’t get how to do the mean and median or mode
Sonja [21]

Hey there! I don't see a number set here, so instead I will do my best to explain what each is and how to find it.

Mean - This is the average of all of the numbers. To find the mean, add up all of the numbers. Then, divide that sum by the number of values you added up.

Median - This is the middle number in your set of data. It is not influenced by outliers, like the mean. Repeat values do count, and you have to use all of your data values, including those repeats, to find an accurate median. To find the median, put all your data values in order from smallest to largest. Begin by crossing out one number on each side (2 total each time) until you get to a middle one or two numbers. If you have one number remaining, then that is your median. If you have two numbers remaining, add those numbers together and divide by 2.

Mode - This is the number, or numbers, that appear the most. For example, if the number 4 appears 10 times in a data set, but the number 2 appears only 4 times, then number 4 is the mode (if the data set is made up of only 4's and 2's). To find the mode, look for the number that appears more often than the rest. Count up the number of times each number occurs and find the one with the highest number of occurrences. That is your mode.

Range - This is the span of your data set. To find the range, subtract the smallest number in your data set from the largest number in your data set. It should look like this: maximum - minimum = range.

Hope this helps!! :)

4 0
3 years ago
Read 2 more answers
The rate of change of the mass, A, of salt at time t is proportional to the square of the mass of salt present at time t. Initia
Brums [2.3K]

Answer:

(a) -dA/dt = kA², A₀ = 10

(b) A =10/(1+ kt)

(c) t > 60 h

Step-by-step explanation:

(a) Find the IVP

A differential equation with an initial condition y₀ = f(x₀) is called an initial value problem.

The rate of decrease of A is proportional to A², and A₀ = 10, so the IVP is

-dA/dt = kA², A₀ = 10

(b) Solve the IVP

\begin{array}{rcl}-\dfrac{\text{d}A}{\text{d}t} & = & kA^{2}\\\\\dfrac{\text{d}A}{A^{2}} & =&-k\text{d}t\\\\-\dfrac{1}{A} & = & -kt + C\\\\\dfrac{1}{A} & = & kt + C\\\\\end{array}

Apply the initial condition: A₀ = 10 (when t = 0)

\dfrac{1}{10} = C\\\\\dfrac{1}{A} = kt + \dfrac{1}{10}\\\\\dfrac{10}{A} = 10kt + 1\\\\\mathbf{A} = \mathbf{\dfrac{10}{1+ kt}}

(c) Find the time when A(t) < 1

(i) Find the value of k (A₁₀ = 4)

\begin{array}{rcl}A& =&\dfrac{10}{1+ kt}\\\\4 & =& \dfrac{10}{1 + 10k}\\\\4 + 40 k & = & 10\\\\40k & = & 6\\k & = & 0.15\\\end{array}\\\\\mathbf{A} =\mathbf{ \dfrac{10}{0.15t + 1}}

(ii) Find t when A < 1

\begin{array}{rcl}A(t) & < & 1\\\dfrac{10}{0.15t + 1} & < & 1\\\\10 & < & 0.15t + 1\\9 & < & 0.15t\\t & > & 60\\\\\end{array}\\\mathbf{A < 1} \textbf{ when }\mathbf{ t >60}

The figure below shows the graph of A vs t.

6 0
3 years ago
Which numbers are solutions to the inequality 2x – 1 &gt; x + 2? Check all of the boxes that apply.
Natasha_Volkova [10]

Answer:

Any number greater than 3.

Step-by-step explanation:

To find the answers to this question, start by solving the inequality for x.

2x - 1 > x + 2

x - 1 > 2

x > 3

Using this, we now know that any number that is greater than 3 would work for this inequality.

7 0
4 years ago
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