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Ray Of Light [21]
3 years ago
15

Please help me with this question

Mathematics
2 answers:
Iteru [2.4K]3 years ago
5 0

Answer: E) w = (t+8)/3

Step-by-step explanation:

Solve for <em>w</em> in terms of <em>t</em> means you have to isolate <em>w</em>.  Thus, simply do the following:

3w-8=t\\3w=t+8\\w=\frac{t+8}{3}

Hope it helps <3

romanna [79]3 years ago
3 0

Answer:

E.

Step-by-step explanation:

so first you would add 8 to both sides to get

3w = t + 8

then divide both sides by 3

w = (t + 8) / 3

So the answer is E.

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1 year ago
Total brain fart! 24+5x=-x+6(5a-4)
kow [346]

Answer:

When solving for x, answer = \large\boxed{x = 5a - 8}

When solving for a, answer = \large\boxed{a = 1/5x + 8/5}

Step-by-step explanation:

24 + 5x = -x + 6(5a - 4)

Start by multiplying 6 by the values in the parenthesis

24 + 5x = -x + 30a - 24

Add 24 to both sides of the equation

48 + 5x = -x + 30a

Add 1x to both sides of the equation

48 + 6x = 30a

Subtract 48 from both sides of the equation

6x = 30a - 48

Divide both sides of the equation by 6

x = 5a - 8 (Answer when solving for x)

Add 8 to both sides of the equation

x + 8 = 5a

Divide both sides of the equation by 5

a = 1/5x + 8/5 (Answer when solving for a)

-----------------------------------------

When solving for x, answer = \large\boxed{x = 5a - 8}

When solving for a, answer = \large\boxed{a = 1/5x + 8/5}

Hope this helps :)

3 0
3 years ago
The angle bisector of ∠ACD in rhombus ABCD makes a 64° angle with the diagonal BD. Find the measure of ∠BAD.
saveliy_v [14]
The complete question in the attached figure

we know that
the diagonals of a rhombus intersect to form right angles, 
so
angle ACE is ----------> (90°-64°)-----------> 26° 
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°

 The diagonals are angle bisectors to the opposite corners
so 
ACD = ACB = 52° 
and 
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so 
BAD = BCD = 104°

the answer is 
angle BAD=104°

3 0
3 years ago
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