Question

The vector v has initial point P(1, 0) and terminal point Q that is on the y-axis and above the initial point. Find the coordinates of terminal point Q such that the magnitude of the vector v is 65 .

Answer 1

Answer:

The terminal point is Q(0,4)

Step-by-step explanation:

We are given the following in the question:

Initial point of vector, P(1,0)

The terminal point Q lies on the y-axis, thus Q have coordinates of the form:

$Q(0,y)$

The magnitude of the vector is $\sqrt{65}$

Magnitude is given by:

$v = \sqrt{(x_2-x_2)^2+(y_2-y_1)^2}\\\sqrt{65}=\sqrt{(0-1)^2+(y-0)^2}\\\sqrt{65}=\sqrt{1+y^2}\\65 = 1+y^2\\y^2 = 64\\y = \pm 8$

But since the terminal point is above the initial point, thus,

$y > 0\\\Rightarrow y = 4$

Thus, the terminal point is Q(0,4)