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3 years ago

I'll give a brainliest PLZ HELPP

Mathematics

2 answers:

Sav [38]3 years ago

8 0

Answer:

This is your answer ☺️☺️☺️

dlinn [17]3 years ago

5 0

M = 18 also for future use download microsoft math solver on your phone or you can go on the laptop too

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How many 4-digit multiples of 21 and 15 are there and 4-digit multiples of either 21 or 15 are there?

salantis [7]

Answer:

943

Step-by-step explanation:

21| 1000

| ----------

47 | 13

21-13=8

1000+8=1008

21|9999

|---------

476|3

9999-3=9996

1008,1029,...,9996

let n be number of terms

a=1008,d=21,l=9996

9996=1008+(n-1)21

9996-1008=(n-1)21

8988=(n-1)21

n-1=8988/21

n-1=428

n=428+1=429

again 15|1000

|---------

66|10

15-10=5

1000+5=1005

15|9999

| ---------

666|9

9999-9=9990

1005,1020,...,9990

a=1005,d=15,l=9990

let n be number of terms.

9990=1005+(n-1)15

9990-1005=(n-1)15

8985=(n-1)15

n-1=8985/15

n-1=599

n=599+1=600

21=3×7

15=3×5

L.C.M.=3×5×7=105

105)1000(9

-945

____

105-55=50

1000+50=1050

105)9999(

-945

---------

549

- 525

-------

9999-24=9975

1050,1155,...,9975

let n be number of terms.

d=105

l=a+(n-1)d

9975=1050+(n-1)105

9975-1050=(n-1)105

8025=(n-1)105

n-1=8925/105

n-1=85

n=85+1=86

so there are 86 multiples of 21 and 15

(A∪B)=A+B-(A∩B)

multiples of 21 or 15=429+600-86=1029-86=943

4 0

3 years ago

The ratio of length to width on a rectangle is

kvasek [131]

Answer:

$Let~the~length~of~rectangle~be~'l'~and~its~width~be~'b'.\\According ~to ~question,\\l:b=11:3\\or, \frac{l}{b} =\frac{11}{3} \\or, l = \frac{11b}{3}\\Also,\\Perimeter~of~the~rectangle=308\\or, 2(l+b)=308\\or, l+b=154\\or, \frac{11 b}{3}+b =154 \\or, \frac{11b+3b}{3} =154\\or, 14b = 154(3)\\or, b=33 units\\So, ~the~width~of~rectangle~is~33units.$

Alternative method:

$Let~the~length~and~width~of~the~rectangle~be~11x~and~3x.\\Given,\\Perimeter~of~the~rectangle = 308\\or, 2(11x+3x)=308\\or, 14x = 154\\or, x = 11\\Now,\\Width~of~the~rectangle,3x = 3(11)=33 units\\So,~the~width~of~the~rectangle~is~33units.$