0.5 = 0.500
0.485<0.500
hope that helps!
it's 51 but i would give brainlyst to the other person so yeah hope this help you :)
Answer:
- Average age of the employees in 2003 = 57.216
- Average age of the employees in 2009 = 59.184
Step-by-step explanation:
We are given the function A(s) as;
A(s) = 0.328*s + 50 where s = number of years since 1981; that is,
s = 0 for 1981 and s = 9 for 1990
A(s) = the average age of an employee
- Now, the average age of the employees in 2003, A(22) = 0.328*22 + 50
Here s = 22 because 2003 - 1981 = 22 years
Therefore, average age of the employees in 2003 = 7.216 + 50 = 57.216 .
- Average age of the employees in 2009, A(28) = 0.328*28 + 50
Here, s = 28 because 2009 - 1981 = 28 years
Therefore, average age of the employees in 2009 = 9.184 + 50 = 59.184 .
Answer:
y = -3x + 12/2
Step-by-step explanation:
Step 1: Add -x to both sides
x + 2/3 + -x = 4 + -x
2/3y = -x + 4
Step 2: Divide both sides by 2/3
2/3y ÷ 2/3 = -x + 4 ÷ 2/3
y = -3x + 12/2