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WINSTONCH [101]
2 years ago
7

15. Cedric lives at one end of Main Street, and Landon lives at the other end of the street. Main Street is 6.02 Kilometers long

. Cedric walks 3.9 kilometers toward Landon's house. How many more meters must Cedric walk to arrive at Landon's house? 2.12 m 9,920 m 2,120 m 3,920 m
Mathematics
1 answer:
emmainna [20.7K]2 years ago
7 0

Answer:

2,120 m

Step-by-step explanation:

Cedric lives at one end of Main Street, and Landon lives at the other end of the street

Main Street is 6.02 Kilometers long. Cedric walks 3.9 kilometers toward Landon's house.

Step 1

We calculate the kilometers Cedric has to walk to arrive at Landon's house

This is given as:.

6.02km - 3.9 km

= 2.12 km

Step 2

How many more meters must Cedric walk to arrive at Landon's house?

We convert from km to m

1 km = 1000m

2.12km = x

Cross Multiply

x = 2.12 × 1000m

x = 2120 m(meters)

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Given :

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Let "S" be small boxes and "L" be large boxes.

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The number of small boxes is 8 and that of the large boxes is 11.

Step-by-step explanation:

Each small box of paper weighs 50 pounds and each large box of paper

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x + y = 19 ............ (1) and

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Now, solving equations (1) and (2) we get,

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<u>Step-by-step explanation:</u>

Let's compare the values of f(x) and g(x) when x = 0, 2, 8, and 4

<u>      f(x)       </u>                      <u>      g(x)        </u>            <u>Comparison</u>

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f(2) = 2(2) - 3                     g(2)=\dfrac{3}{2}(2)+1

     = 1                                      = 4                     f(2) < g(2)

f(8) = 2(8) - 3                     g(8)=\dfrac{3}{2}(8)+1

     = 13                                   = 13                     f(8) = g(8)

f(4) = 2(4) - 3                     g(4)=\dfrac{3}{2}(4)+1

      = 5                                   = 7                       f(4) < g(4)


The only statement provided that is true is f(8) = g(8)




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