Answer:
1. x = 7
2. x = -5
Step-by-step explanation:
1. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: 2*x+5*(6*x-9)-(179)=0
Pull out like factors 6x - 9 = 3 • (2x - 3)
(2x + 15 • (2x - 3)) - 179 = 0
Pull out like factors: 32x - 224 = 32 • (x - 7)
Solve: x-7 = 0
Add 7 to both sides of the equation = 7
2. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: -40-(6*x-5*(-4*x-18))=0
Pull out like factors: -4x - 18 = -2 • (2x + 9)
-40 - (6x - -10 • (2x + 9)) = 0
Pull out like factors: -26x - 130 = -26 • (x + 5)
-26 • (x + 5) = 0
Solve: x+5 = 0
Subtract 5 from both sides of the equation: x = -5
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Answer:
the answer is B
Step-by-step explanation:
75 is a one time payment. 25 is the amount that you will pay permonth
(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x -5/3.
We have given
-3x+4 > 9
Required values of x.
State the values of x within -3 and 3.
subtract 4 from both sides,
-3x+4-4>9-4
<h3>What is the meaning of like terms?</h3>
like terms are terms that have the same variables and powers. The coefficients do not need to match.
Collect Like Terms
-3x > 5
(-3x)(-1) < 5(-1)
3x < -5
Divide both sides by 3
3x/3 < -5/3
x < -5/3
(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x is -5/3.
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Answer:
1,890 minuts
Step-by-step explanation:
3 weeks = 7 days x 3 = 21 days
He rides his bike for "45 minutes to get to school and 45 minutes to get home" which is 90 minutes per day.
Therefore, in total, he rode for 21 days x 90 minutes per day = 1,890 minutes
<h3>Explanation:</h3>
GCF: the greatest common factor of numerator and denominator is a factor that can be removed to reduce the fraction.
<em>Example</em>
The numerator and denominator of 6/8 have GCF of 2:
6/8 = (2·3)/(2·4)
The fraction can be reduced by canceling those factors.
(2·3)/(2·4) = (2/2)·(3/4) = 1·(3/4) = 3/4
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LCM: the least common multiple of the denominators is suitable as a common denominator. Addition and subtraction are easily performed on the numerators when the denominator is common.
<em>Example</em>
The fractions 2/3 and 1/5 can be added using a common denominator of LCM(3, 5) = 15.
2/3 + 1/5 = 10/15 + 3/15 = (10+3)/15 = 13/15