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strojnjashka [21]
3 years ago
12

Tennis balls with a diameter of 2.5 in.are sold in cans of three. The can is a cylinder. What is the volume of the space in the

can that is not occupied by tennis balls? Assume the tennis balls touch the can on the sides, top, and bottom.
Mathematics
1 answer:
Alexxandr [17]3 years ago
3 0

Using 3.14 for PI.

The radius of a ball and the can is half the diameter = 1.25

The height of the can is the height of 3 diameters = 7.5

Volume of one tennis ball:

4/3 x PI x 1.25^3 = 8.18 cubic inches.

Volume of 3 tennis balls: 3 x 8.18 = 24.54 cubic inches.

Volume of can:

PI x 1.25^2 x 7.5 = 36.80 cubic inches.

Space = 36.80 - 24.54 = 12.26 cubic inches.

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n200080 [17]

I believe it is 20,416.67

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2 years ago
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The difference between the product of 4 and a number 6
Mice21 [21]

Answer:

If we call our unknown value x, then we can say that

The "product of 4 and a number" is 4x

The "difference between" 4x and 6 is 4x - 6

Step-by-step explanation:

8 0
3 years ago
Se corta una manzana en 12 partes, se comen ocho partes. Qué fracción simplificada a su mínima expresión representa la cantidad
lakkis [162]

Answer:

A. 1/3

Step-by-step explanation:

Dado que:

una manzana se corta en 12 partes y se comen ocho partes.

La fracción de manzanas consumidas = 8/12

= 2/3

La fracción de manzanas que quedan = valor original de la manzana que se corta - la fracción de la manzana que se come

La fracción de manzanas que quedan  =1-  \dfrac{8}{12}

La fracción de manzanas que quedan  =\dfrac{12-8}{12}

La fracción de manzanas que quedan =\dfrac{4}{12}

A la fracción más baja; obtenemos = 1/3

6 0
3 years ago
I don't understand this
timama [110]
The product of 0.02 and 0.7 is 0.014. Notice the additional zero in the number 0.'0'2. Product is the total of two numbers multiplied or times (x).

This is the solution:
0.02
0.7
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0.014

So the right answer is A. 0.014.
7 0
3 years ago
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A three inch diameter pulley on an electric motor that runs at 1800
Bezzdna [24]

Answer:

a) 3 inch pulley: 11,309.7 radians/min

6) 6 inch pulley: 5654.7 radians/min

b) 900 RPM (revolutions per minute)

Step-by-step explanation:

Hi!

When a pulley wirh radius R rotantes an angle θ, the arc length travelled by a point on its rim is Rθ.  Then the tangential speed V is related to angular speed  ω as:

V=R\omega

When you connect two pulleys with a belt, if the belt doesn't slip, each point of the belt has the same speed as each point in the rim of both pulleys: Then, both pulleys have the same tangential speed:

\omega_1 R_1 = \omega_2 R_2\\

\omega_2 = \omega_1 \frac{R_1}{R_2} =1800RPM* \frac{3}{6}= 900RPM

We need to convert RPM to radias per minute. One revolution is 2π radians, then:

\omega_1 = 1800*2\pi \frac{radians}{min} = 11,309.7\frac{radians}{min}

\omega_2 = 5654.7 \frac{radians}{min}

The saw rotates with the same angular speed as the 6 inch pulley: 900RPM

3 0
3 years ago
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