Answer: Ali would need to drive 350 miles for the two plans to cost the same.
Step-by-step explanation:
This question can be solved by creating two equations using the information supplied in the question and then solving these simultaneously.
Let the cost be C.
Let the number of miles be M.
Let the initial payment be i.
Let the rate per mile driven be R.
Plan 1:
C = i+R×M
C = 70+0.60M ... equation 1
Plan 2:
C = i+R×M
C = 0+0.80M
C = 0.80M ...equation 2
Substituting equation 2 into equation 1:
0.80M = 70+0.60M
0.80-0.60M = 70
0.20M = 70
M = 70/0.20
M = 350 miles
6.0 x 10^-5 I think is the answer
D≈2π(6371-1737.5)
d≈9267π
d≈29113.1km (to nearest tenth of a kilometer)
Answer:
$625 (but it's really $763.14)
Step-by-step explanation:
Use the formula I=P(1+r)^t
April=25000(1.04)^5=$30416.32
May=25000(1.0375)^6=$31179.46
$31179.46-$30416.32=$763.14
So $625 is the closest answer
