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2 years ago

Solve the system of equations y=x^2-3x+4 x+y=4 show all work please!

Mathematics

1 answer:

Debora [2.8K]2 years ago

6 0

Answer:

(0,4)

(2,2)

Step-by-step explanation:

y=x^2-3x+4

x+y=4

the second one can be rewritten as y=4-x

so the system becomes

y=x^2-3x+4

y=4-x

therefore 4-x = x^2-3x+4

that is x^2-2x=0

we can write it as x(x-2)=0 a product is = 0 when one of its factors = 0

so the solutions for x are: x=0 and x-2= 0 that means x=2

to get y you simply use 0 and 2 as value of x for any of the two equations

and you get y=4 and y=2 respectively

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