Answer:
On the coordinate grid, the graph of y = -x - 1 is shown
1 answer:
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Answer:
The point is (7,0).
Step-by-step explanation:
The equation of a linear function in point-slope form is as follows :
...(1)
Where
(x₁,y₁) are the coordinates of the point which the line passes through it and (x,y).
Harold correctly wrote the equation y= 3(x–7)
or we can write it as :
y-0=3(x-7) ...(2)
Comparing equations (1) and (2), we get :
x₁ = 7 and y₁ = 0
So, the point is (7,0).
The correct option is (c).
Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
