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3 years ago

Given ab/bc = fe/ed find ac

1 answer:

6 0

Well, you can cancel out the b and e, so a/c = f/d.

Then you cancel out a on the left side of the equation by multiplying both sides by 1/a which then gives you c = f/ad.

Hope this helps!

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What is the order of 75%,1/3,3/8 and0.625 from least to greatest

Oksanka [162]

Answer:

1/3 , 3/8 , 0.625 , 75%

Step-by-step explanation:

75/100 = 0.750

1/3 = 0.330

3/8 = 0.375

5 0

3 years ago

Read 2 more answers

Height for each toddler at Mrs.orlando daycare

Tatiana [17]

1=81 centimetres
1=82 centimetres
2=83 centimetres
3=84 centimetres
1=85 centimetres

8 0

3 years ago

A tree in leilas backyard has been growing for 3 1/5 years. It is 3/4 meters tall how many meters per year?

IgorC [24]

Answer:

The tree grew 15/64 meters per year.

Step-by-step explanation:

Given

Length of a tree = 3/4 meters

Total time taken by the tree to grow 3/4 taller = 3 1/5 or 16/5 years

To determine

Per year growth of the tree in meters

Per year growth of the tree in meters can be determined by dividing the total length of a tree i.e. 3/4 meters by the total time taken by the tree to get 3/4 taller.

Per year growth of tree = Total Length / Total time to grow

= 3/4 ÷ 16/5

= 3/4 × 5/16

= [3×5] / [4×16]

= 15/64 meters

Therefore, the tree grew 15/64 meters per year.

4 0

3 years ago

What is the slope of the line passed through the points ( 1, -5) and 4,1?

Allisa [31]

If you use the slope formula, the answer is m = 2

8 0

3 years ago

How does the graph of f(x)=3lx+2l+4 relate to its parent function?

Sergeeva-Olga [200]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units

check the picture below

7 0

3 years ago