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Phantasy [73]
3 years ago
14

Height for each toddler at Mrs.orlando daycare

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0
1=81 centimetres
1=82 centimetres
2=83 centimetres
3=84 centimetres
1=85 centimetres
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Rewrite each fraction with a denominator of 10 7/2 3/5
Vaselesa [24]

Answer:

  • \frac{7}{2}=\frac{35}{10}
  • \frac{3}{5}=\frac{6}{10}

Step-by-step explanation:

Given the fraction

\frac{7}{2}

Multiplying numerator and denominator by 5

\frac{7}{2}\times \frac{5}{5}

=\frac{35}{10}

Therefore,

  • \frac{7}{2}=\frac{35}{10}

Similarly,

Given the fraction

\frac{3}{5}

Multiplying numerator and denominator by 2

\:\frac{3}{5}\times \:\frac{2}{2}

\frac{3}{5}\times \:\frac{2}{2}=\frac{6}{10}

Therefore,

  • \frac{3}{5}=\frac{6}{10}
8 0
3 years ago
Question 11
Gre4nikov [31]
The question ask on which of the following in you choices is the equation that best compares the slops of the two function and the best answer would be letter D. Slope of function B = - Slope of Function A, I hope you are satisfied with my asnwer and feel free to ask for more 
7 0
3 years ago
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(-(-)(-)(-10x))=-5 solve for x
kirza4 [7]
A negative times a negative is a positive so...

( - ) ( - ) ( - ) ( -10x ) = -5

10x = -5

x = -5/10

x = -1/2
4 0
3 years ago
What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the
marishachu [46]
The sum of all the measurements is just the average times the number.

\bar x = \frac{1}{n} \sum_{i=1}^n x_i

\sum_{i=1}^n x_i = n \bar x

So if the average of all 92 is 7 the sum of those is 92 \times 7

The average of the last two is 7.2 so their sum is 2 \times 7.2

That means the sum of the first 90 is 92 \times 7 - 2 \times 7.2

so the average of the first 90 is

 \dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556 cm



7 0
3 years ago
A frightened child is restrained by her mother as the child slides down a frictionless playground slide. If the force on the chi
MissTica

Answer:

Step-by-step explanation:

Given

Restrained Force F=116 N

Increase in Kinetic Energy \Delta K.E.=30 J

Distance moved d=1.9 m

Work done by all the forces is equal to change in Kinetic Energy of Object i.e. by gravity force, Normal force and Applied Force

\Delta K.E.=W_g+W_f+W_N

30=W_g-F\cdot d

30=W_g-116\cdot 1.9

W_g=250.4 J

(b)In absence of applied force thus

work done by gravity will be equal to  change in kinetic Energy

change in Kinetic Energy=210 J

6 0
3 years ago
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