The quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3
<h3 /><h3>How to solve fraction</h3><h3 />
n³ / (2n - 6) ÷ n³ / (3n - 9)
- multiply by the reciprocal of n³ / (3n - 9)
= n³ / (2n - 6) × 1 / n³ / (3n - 9)
= 2n - 6 / 3n - 9
= 2(n - 3) / 3(n - 3)
= 2/3
Therefore, quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3
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Notice that 38 and 52 make a total of 90
sinA=cos(90-A)
sin38=cos52, therefore the answer is zero
Just do 6 x 0.2 to reverse the division
So the answer is 1.2
I think
I'm pretty sure that it's b. That's assuming that you find the negative of b^2 and not the square of negative b.
Answer:
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