1. -3
2. 28
3. 88
4. -5
5. -28
Answer: 0.0241
Step-by-step explanation:
This is solved using the probability distribution formula for random variables where the combination formula for selection is used to determine the probability of these random variables occurring. This formula is denoted by:
P(X=r) = nCr × p^r × q^n-r
Where:
n = number of sampled variable which in this case = 21
r = variable outcome being determined which in this case = 5
p = probability of success of the variable which in this case = 0.31
q= 1- p = 1 - 0.31 = 0.69
P(X=5) = 21C5 × 0.31^5 × 0.69^16
P(X=5) = 0.0241
<h2>
<u>Requi</u><u>red</u><u> Answer</u><u> </u><u>:</u><u>-</u></h2>
Given system of linear equations are ,
And we need to find the Solution of the linear equation . So let's Firstly number the equations .
<u>→</u><u> </u><u>Multipl</u><u>ying</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>by</u><u> </u><u>3</u><u> </u><u>,</u>
=> 3 ( x + y ) = 2*3
=> 3x + 3y = 6
<u>→</u><u> </u><u>Addin</u><u>g</u><u> </u><u>the</u><u> </u><u>two</u><u> </u><u>equations </u><u>,</u><u> </u>
=> 3x + 3y -3y + y = 6 + 2
=> 4y = 8
=> y = 8/4
=> y = 2
<u>→</u><u> </u><u>Put</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>in</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>,</u>
=> x + y = 2
=> x + 2 = 2
=> x = 2- 2
=> x = 0
<h3>
<u>★</u><u> </u><u>Hence</u><u>
the required solution is ( 0 , 2 ) .</u></h3>
Answer:
530
Step-by-step explanation:
Answer: Perpendicular because the second line has a 2/3 slope and starts at 4.