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fomenos
3 years ago
10

Sally Harris, a young mother, is twenty-six years old. She wishes to purchase $15,000 of a ten-year term insurance. What will be

her annual premium? 64.35 62.25 63.00 61.50
Mathematics
2 answers:
saw5 [17]3 years ago
6 0

Answer:61.50

Step-by-step explanation:

MArishka [77]3 years ago
3 0

Answer: 61.50

Step-by-step explanation:

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Please help me what is the measure of it ?
never [62]

Answer:

115

Step-by-step explanation:

A supplementary line equals 180

You have to subtract 65 by 180

which gives you 115

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Find the equation of the line with slope m=1 that contains the point (7,5).
katovenus [111]

Answer:

y = x - 2

Step-by-step explanation:

y = mx + b

5 = 1 (7) + b

5 = 7 + b

b = -2

So...

y = x - 2

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2 years ago
5/6 of 15 i need help????????????
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Write the word sentence as an equation. 12 less than a number m equals 20.
PolarNik [594]

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5 0
3 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
3 years ago
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