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jenyasd209 [6]
3 years ago
11

Mickey keeps picking playing cards out of a standard deck of 52 cards, hoping that she will

Mathematics
1 answer:
andrew-mc [135]3 years ago
7 0

Answer:

03%

Step-by-step explanation:

In this situation Mickey should have drew first 7 cards that are not diamond and then on the 8th attempt she should draw an ace.

Let A be the event of drawing 7 cards which are not diamond and B the event of drawing an ace card. therefore required probability is P(A∩B)=P(A)*P(B)

Now, there are 13 diamonds and 39 other cards. Hence,

P(A)=(\frac{39}{52})⁷=0.1335

After drawing 7 non-diamond cards, the 8th card must be a diamond.Hence,

P(B)=\frac{13}{52}=0.25

Hence, P(A∩B)=P(A)*P(B)=0.1335*0.25=0.033(approximately 0.03,i.e. 3%)

Therefore probability that Mickey will draw her first diamond on the 8th

attempt is 3%

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