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svet-max [94.6K]
2 years ago
12

In one city, 75 percent of residents report that they regularly recycle. In a second city, 90 percent of residents report that t

hey regularly recycle. Simple random samples of 75 residents are selected from each city. Which of the following statements is correct about the approximate normality of the sampling distribution of the difference in sample proportions of residents who report that they regularly recycle?
a. The sampling distribution is approximately normal because both sample sizes are large enough.
b. The sampling distribution is not approximately normal because although the sample size for the first city is large enough, the sample size for the second city is not large enough.
c. The sampling distribution is not approximately normal because although the sample size for the second city is large enough, the sample size for the first city is not large enough.
d. The sampling distribution is not approximately normal because neither sample size is large enough.
e. There is not enough information provided to determine whether the sampling distribution is approximately normal.
Mathematics
1 answer:
Paraphin [41]2 years ago
6 0

can you show me a picture then maybe i can help you

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Northwest Molded molds plastic handles with a variable cost of $1.00 per handle. The fixed cost to run the molding machine is $2
ASHA 777 [7]

Answer:

To break even it  must be molded 1280 handles weekly.

The profit if 1500 handles are produced and sold is $440

Step-by-step explanation:

To break even, the amount of total cost must be the same as the amount of revenues.  

Total Cost is Fixed cost plus unitary variable cost multiplied by the produce quantity.  

Total cost= FC + vc*Q

Where

FC=Fixed cost

vc=unitary variable cos

Q=produce quantity

Revenue= Price * Q

Break even FC + vc*Q=Price * Q

Isolating Q

FC=(Price * Q)-(vc*Q)

FC=(Price-vc) * Q

Q= FC/(Price-vc)

Q= $2560/($3.00-$1.00)=1280

If we sold 1500 handles

Profit = Revenue- Total cost =(Price * Q)-(FC + vc*Q)

P=$3.00 *1500-$2560 - $1.00*1500=

P=$4500-$2560-$1500=440

8 0
3 years ago
A car dealership recently started tracking the number of cars sold each month based on the number of commercials aired on TV tha
Firlakuza [10]
B you have to get what your gut says
8 0
3 years ago
Read 2 more answers
The sides of a right triangle have a relationship as depicted below, where x is the length of the longer leg in inches.
Ratling [72]
The equation to represent the area of the triangle would be:
y = 1/2(x²) - (7/2)x

The equation to represent the perimeter of the triangle would be:
y = 3x - 6

The solutions to the system would be (12, 30) or (1, -3).  The only viable solution is (12, 30).

Explanation
The area of a triangle is found using the formula
A = 1/2bh

For our triangle, b = x and h = x-7, so we have:
A = 1/2(x)(x-7)
A = 1/2(x²-7x)
A = 1/2(x²) - (7/2)x

We will replace A with y, so we have:
y = 1/2(x²) - (7/2)x

The perimeter of a triangle is found by adding together all sides, so we have:
P = (x-7) + x + (x+1)

Combining like terms we get:
P = 3x - 6

We will replace P with y, so we have:
y = 3x - 6

Since both equations have y isolated on one side, it will be easy to use substitution to solve the system:

3x - 6 = 1/2(x²) - (7/2)x

It's easier to work with whole numbers, so we will multiply everything by 2:
6x - 12 = x² - 7x

We want all of the variables on one side, so we will subtract 6x:
6x - 12 - 6x = x² - 7x - 6x
-12 = x² - 13x

When solving quadratics, we want the equation equal to 0, so we will add 12:
-12+12 = x² - 13x + 12
0 = x² - 13x + 12

This is easy to factor, as there are factors of 12 that sum to -13; -12(-1) = 12 and -12+-1 = -13:
0 = (x-12)(x-1)

Using the zero product property, we know that either x-12=0 or x-1=0; therefore x=12 or x=1.

Putting these back into our equation for perimeter (the simplest one) we have:
y = 3(12)-6 = 36-6 = 30; (12, 30);
y = 3(1) - 6 = 3 - 6 = -3; (1, -3)

We cannot have a negative perimeter, so the only viable solution is (12, 30).
8 0
2 years ago
Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant
son4ous [18]
The chain rule states that

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

Since \ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2), you have

\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}
\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}
\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}

and

\dfrac{\mathrm dx}{\mathrm dt}=\cos t
\dfrac{\mathrm dy}{\mathrm dt}=-\sin t
\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t

Also, since x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t, the derivative is

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}
\dfrac{\mathrm dw}{\mathrm dt}=\tan t
4 0
3 years ago
Read each statement then select whether it is true or false.
Marina CMI [18]

Answer:

1) true

2) false

3) false

4)True

4 0
2 years ago
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