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andrezito [222]
3 years ago
7

Tentukan hasil dari (2√3–5√7)(2√3–5√7)= pakai cara

Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

solving the expression \left(2\sqrt{3}-5\sqrt{7}\right)\:\left(2\sqrt{3}-5\sqrt{7}\right) we get \mathbf{187+20\sqrt{21}}

Step-by-step explanation:

We need to solve: \left(2\sqrt{3}-5\sqrt{7}\right)\:\left(2\sqrt{3}-5\sqrt{7}\right)

We can write it as:

\left(2\sqrt{3}-5\sqrt{7}\right)\:\left(2\sqrt{3}-5\sqrt{7}\right)\\=\left(2\sqrt{3}-5\sqrt{7}\right)^2

We can use formula: a^2-b^2=a^2-2ab+b^2

=\left(2\sqrt{3})^2-2(2\sqrt{3})(-5\sqrt{7})+(-5\sqrt{7}\right)^2\\=4(3)+20\sqrt{3}\sqrt{7}+25(7)\\=12+20\sqrt{3\times 7}+175\\=187+20\sqrt{21}

So, solving the expression \left(2\sqrt{3}-5\sqrt{7}\right)\:\left(2\sqrt{3}-5\sqrt{7}\right) we get \mathbf{187+20\sqrt{21}}

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In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

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So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
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You have ​$55 in your bank account. Each week you deposit $8 from your allowance and $15 from your paycheck. The equation b=55+(
scoundrel [369]
<h3>After 6 weeks from now you will have $190 in your bank account</h3>

<em><u>Solution:</u></em>

Given that,

You have ​$55 in your bank account

Each week you deposit $8 from your allowance and $15 from your paycheck

<em><u>The equation that gives the amount b in your account after w weeks is:</u></em>

b = 55 + (15 + 8)w

<em><u>How many weeks from now will you have $190 in your bank account ?</u></em>

b = 190

w = ?

Therefore,

190 = 55 + (15 + 8) w

190 = 55 + 23w

23w = 190 - 55

23w = 135

Divide both sides by 23

w = 5.869 \approx 6

Thus after 6 weeks from now you will have $190 in your bank account

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