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dybincka [34]
3 years ago
6

4. In the Department of Natural Sciences, 14 faculty members have a PhD, and 30 faculty

Mathematics
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

  8

Step-by-step explanation:

We can start by making the table below to show the given numbers (red) and to assign a variable (x) to <em>the number we want to find: female PhDs</em>.

By subtracting the female numbers from the totals, we can find the corresponding numbers of male PhDs and non-PhDs.

The number of male non-PhDs is twice the number of male PhDs, so we have ...

  2(14 -x) = 20 -x

  28 -2x = 20 -x . . . . eliminate parentheses

  8 = x . . . . . . . . . . . .add 2x-20

The number of female faculty with PhDs is 8.

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mestny [16]

Answer:

All three are rational numbers.

Step-by-step explanation:

I used Desmos (a graphing calculator online) and the roots were all able to be written with fractions.

6 0
3 years ago
Given: BC bisects DBE. Prove: ABD is congruent to ABE
Arada [10]

Answer:

See below

Step-by-step explanation:

BC bisects <DBE and if AC is a straight line then you have that:

<ABD + <DBC = 180 (straight angle because of line AC)

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3 years ago
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djyliett [7]

Input (x-value)

Output (y-value)

You need to find the x-value that produces a y-value of -1. Since you know:

y = -1       Use the rule, and substitute/plug this into the equation

y = -2x + 33       Plug in -1 for "y" in the equation since y = -1

-1 = -2x + 33        Subtract 33 on both sides

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podryga [215]

Answer:

=  \frac{5}{2}  = 2 \frac{1}{2}

Step-by-step explanation:

( \frac{625}{16}  {)}^{ \frac{1}{4} }  \\  \sqrt[4]{ \frac{625}{16} }  =  \frac{ \sqrt[4]{625} }{ \sqrt[4]{16} }   \\  \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{16} }  =  \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{ {2}^{4} } }  =  \frac{5}{2}

\boxed{\green{=  \frac{5}{2}  = 2 \frac{1}{2}}}

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sdas [7]
I might be wrong but I think it’s b sorry if wrong :)
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