What if the slope of the graph
1 answer:
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Answer:
3 seconds.
Step-by-step explanation:
We have been given that Sandra throws an object straight up into the air with initial velocity of 38 ft per second from platform that is 30 ft above the ground.
To find the time it will take for object to hit the ground, we will use formula:
, where,
represents initial velocity and
represents initial height.
Upon substituting our given initial velocity and initial height, we will get:
We know that object will hit the ground, when height will be 0, so we will equate object's height equal to 0 and solve for t as:
Divide by 2:
Upon using quadratic formula, we will get:
Since time cannot be negative, therefore, it will take 3 seconds for object to hit the ground.
Answer:
- 150π ft²
- 10π ft.
Step-by-step explanation:
Area of the sector :
Finding the area given r = 30 ft. and θ = 60° :
⇒ Area = π × (30)² × 60/360
⇒ Area = π × 900/6
⇒ Area = 150π ft²
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Length of the arc :
Finding the arc length given r = 30 ft. and θ = 60° :
⇒ Arc Length = 2 × π × 30 × 60/360
⇒ Arc Length = 60/6 × π
⇒ Arc Length = 10π ft.
Answer:
The third quartile is 56.45
Step-by-step explanation:
The given parameters are;
The first quartile, Q₁ = 30.8
The median or second quartile, Q₂ = 48.5
The mean, = 42.0
Coefficient of skewness = -0.38
The Bowley's coefficient of skewness (SK) is given as follows;
Plugging in the values, we have;
Which gives;
-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5
11.704 - 0.38·Q₃ = Q₃ - 66.2
1.38·Q₃ = 11.704 + 66.2 = 77.904
Q₃ = 56.45
The third quartile = 56.45.