If one cup has 5.2 mg then you would need 4 cups to get at least 18 mg.
Answer:
20
Step-by-step explanation:
1/10 of 200 is 20.
Answer:
I'd say that is an "occupancy problem".
I ran a spreadsheet simulation of that and I'd say the probability is approximately .13
Those problems are rather complex to solve. What I think you would have to do is calculate the probability of
A) ZERO sixes appearing in 4 rolls.
B) exactly 1 six appears in 4 rolls.
C) exactly 2 sixes appear in 4 rolls.
D) exactly 3 sixes appear in 4 rolls. and
E) exactly 4 sixes appear in 4 rolls.
4 rolls of a die can produce 6^4 or 1,296 combinations.
A) is rather easy to calculate: The probability of NOT rolling a six in one roll is 5/6. In 4 rolls it would be (5/6)^4 = 0.4822530864
E) is fairly easy to calculate: The probability of rolling one six is (1/6). The probability of rolling 4 sixes is (1/6)^4 = 0.0007716049
Then we need to:
D) calculate how many ways can we place 3 objects into 4 bins
C) calculate how many ways can we place 2 objects into 4 bins
B) calculate how many ways can we place 1 objects into 4 bins
I don't know how to calculate D C and B
Step-by-step explanation:
Answer:
Part a) GK=(7x+1)
Part b) GH=5 units and JK=8 units
Step-by-step explanation:
Part a) what algebraic expression represents GK?
we know that
GK=GH+HJ+JK
step 1
Find GH
we have
GH=GJ-HJ
substitute the given values
GH=(2x+3)-x=x+3
step 2
Find JK
JK=HK-HJ
substitute the given values
JK=(6x-2)-x=5x-2
step 3
Find GK
GK=GH+HJ+JK
we have
GH=x+3
HJ=x
JK=5x-2
substitute
GK=(x+3)+x+(5x-2)
GK=(7x+1)
Part b) If GK=15, what are GH and JK?
we know that
GK=(7x+1)
For GK=15
substitute the value of GK and solve for x
15=(7x+1)
7x=15-1
7x=14
x=2
<u><em>Find the value of GH</em></u>
GH=x+3
substitute the value of x
GH=2+3=5 units
<u><em>Find the value of JK</em></u>
JK=5x-2
substitute the value of x
JK=5(2)-2=8 units
Answer:
On day 0 (starting day), the percentage of petri dish occupied by bacteria was 2.44%
Step-by-step explanation:
Rate of growth = 2 (i.e. doubles every day)
Petri dish was filled to 100% on day 12.
Let
P(0) = percentage of Petri dish occupied on day 0, then
equation of percentage a function of time in x days
P(x) = P(0)*r^x ......................(1)
where
100% = P(12) = p(0) * 2^12 = 4096 P(0)
=>
P(0) = 100% / 4096 = 0.0244%
Next, to find percentage on February 14 (Valentine's day!)
Day 0 is February 9, so February 14 is the fifth day, so x=5.
Substitute x=5 in equation (1) above,
P(x) = P(0)*r^x
P(5) = P(0)*2^5
P(5) = 0.0244*2^5 = 0.0244*32 = 0.781%
Ans. the 0.781% of the petri dish was filled with bacteria after 5 days on February 14th.
