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3 years ago

5

How do you find the third side if a right triangle??

2 answers:

OlgaM077 [116]3 years ago

5 0

Answer:

use the pythagorean theorem

Step-by-step explanation:

lianna [129]3 years ago

4 0

A^2 +b^2=c^2 so let’s say you are solving for your hypotenuse which is the slanted non right angle side would be your c. if your dimensions of the right angle sides are 6 x8 your a would be 6 and your 8 would be b. your equation would look like 6^2 + 8^2 =c^2. 36+64= 100 (your third side)

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The perimeter of a rectangular field is 374 yard. If the length of the field is 99 yards, what is its width?

likoan [24]

The perimeter of a rectangle is 2*L+2*W. Knowing that length is 99, we do 2*99 to get 198.Do 374-198, which is 176, we know that that is twice the length of the width. Therefore the width is 176/2, which is 88.

3 0

3 years ago

Read 2 more answers

What is the diameter of if the circumference of 14

Serggg [28]

Answer:

The diameter would be 4.456338407...

Step-by-step explanation:

This is because if the formula for circumference is C= D(pi) , to find the diameter it's the opposite. D= C/pi

3 0

3 years ago

A manufacturer wants to make open tin boxes from pieces of tin with dimensions 8 in. by 15 in. by cutting equal squares from the

Stells [14]

Answer:

$\frac{5}{3}$ in

Step-by-step explanation:

Let x be the side of square.

Length of box=8-2x

Width of box=15-2x

Height of box=x

Volume of box= $L\times B\times H$

Substitute the values then we get

Volume of box=V(x)= $(8-2x)(15-2x)x=(15x-2x^2)(8-2x)$

$V(x)=120x-30x^2-16x^2+4x^3$

$V(x)=4x^3-46x^2+120x$

Differentiate w.r.t x

$V'(x)=12x^2-92x+120$

$V'(x)=0$

$12x^2-92x+120=0$

$3x^2-23x+30=0$

$3x^2-18x-5x+30=0$

$3x(x-6)-5(x-6)=0$

$(x-6)(3x-5)=0$

$x-6=0\implies x=6$

$3x-5=0\implies x=\frac{5}{3}$

Again differentiate w.r.t x

$V''(x)=24x-92$

Substitute x=6

$V''(6)=24(6)-92=52>0$

Substitute x=5/3

$V''(5/3)=24(5/3)-92=-52$

Hence, the volume is maximum at x= $\frac{5}{3}$

Therefore, the side of the square , $x=\frac{5}{3}$ in cutout that gives the box the largest possible volume.

5 0

2 years ago

Pls help this is an ixl question and it really is hard

valentina_108 [34]

Answer:

It would be the first one... 10:25

Step-by-step explanation:

10/4=2.5

2.5*10=25

2.5*4=10

7 0

2 years ago

Please help me on this problem

Rudik [331]

<h2><em><u>Answer:</u></em></h2>

Total Surface Area = 375 $ft^2$

<h2><em><u>Step-by-step explanation:</u></em></h2>

You need to find the area of the ceiling, floor, the two rectangle walls and the two trapezoid walls

<u>Area of the ceiling:</u>

c = length * width

c = 9*6.5 = 58.5

<u>Area of the 2 rectangle walls:</u>

w = 2(length * width)

w = 2(9 * 8)

w = 2(72)

w = 144

<u>Area of floor:</u>

f = 9 * 7.5

f = 67.5

<u>Area of the two trapezoids:</u>

$t = 2(h * \frac{a + b}{2})$

a = 6.5

b = 7.5

h = 7.5

$t = 2(h * \frac{a + b}{2})$

$t = 2(7.5 * \frac{6.5 + 7.5}{2})$

$t = 2(7.5 * \frac{14}{2})$

$t = 2(7.5 * 7)$

$t = 2(52.5)$

$t = 105$

Total Surface Area = c + w + f + t

Total Surface Area = 58.5 + 144 + 67.5 + 105

Total Surface Area = 375 $ft^2$

8 0

3 years ago