3 years ago

Is -10/3 greater or less that the square root of -9

Mathematics

1 answer:

svp [43]3 years ago

4 0

Step-by-step explanation:

The square root of -9 is greater than that

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2 years ago

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Answer:

$\frac{a^3 b^2}{\frac{1}{a} \frac{1}{b^3}}$

And simplifying we got:

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Step-by-step explanation:

We want to simplify the following expression:

$\frac{a^3 b^2}{a^{-1} b^{-3}}$

And we can rewrite this expression using this property for any number a:

$a^{-1}= \frac{1}{a}$

And using this property we have:

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And simplifying we got:

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