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Afina-wow [57]
3 years ago
5

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 21 meters cubed.

Mathematics
2 answers:
LenaWriter [7]3 years ago
5 0

Answer:

28 meters cubed.

Step-by-step explanation:

Since we know that the volume of a sphere is 4/3 the volume of a cylinder, we can multiply 21*4/3. 21*4 will equal 84 and 84/3 would be 28. So the volume of the sphere would be 28 meters cubed.

liraira [26]3 years ago
5 0

Answer:

14M^3 (c)

Step-by-step explanation:

This was the answer on edge

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If "-3(y-10=9" what is the value of y-12
zvonat [6]

Answer:

the correct answer is -5 since y=7

8 0
2 years ago
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What is 22 nickels equal to?
Viktor [21]
$1.10 is your answer
4 0
3 years ago
So the polynomial 24r squared represents the surface are of a cube a : determine the polynomial that represents the area of one
Naddika [18.5K]

Answer:

a. 4r² b. 2r c. 6 cm

Step-by-step explanation:

The surface area A of the cube is A = 24r². We know that the surface area, A of a cube also equals A = 6L² where L is the length of its side.

Now, equating both expressions, 6L² = 24r²

dividing both sides by 6, we have

6L²/6 = 24r²/6

L² = 4r². Since the area of one face is L², the polynomial that determines the area of one face is A' = 4r².

b.  Since L² = 4r² the rea of one face of the cube, taking square roots of both sides, we have

√L² = √4r²

L = 2r

So, the polynomial that represents the length of an edge of the cube is L = 2r

c. The length of an edge of the cube is L = 2r. When r = 3 cm.

L = 2r = 2 × 3 cm = 6 cm

So, the length of an edge of the cube is 6 cm.

5 0
3 years ago
Help me plz help me
alukav5142 [94]

Answer:

1=3 given

1=2 vertical angles

3=4 vertical angles

2=4 transitive property (?)

Step-by-step explanation:

it's been a while since i've done proofs but i think this is right

4 0
2 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
3 years ago
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