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2 years ago

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 21 meters cubed.

Mathematics

2 answers:

LenaWriter [7]2 years ago

5 0

Answer:

28 meters cubed.

Step-by-step explanation:

Since we know that the volume of a sphere is 4/3 the volume of a cylinder, we can multiply 21*4/3. 21*4 will equal 84 and 84/3 would be 28. So the volume of the sphere would be 28 meters cubed.

liraira [26]2 years ago

5 0

Answer:

14M^3 (c)

Step-by-step explanation:

This was the answer on edge

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Find ST if S(-3, 10) and T(-2, 3)

FrozenT [24]

We have the following points and their coordinates:

$\begin{gathered} S(-3,10), \\ T(-2,3). \end{gathered}$

We must compute the distance ST between them.

The distance ST between the two points is given by:

$ST=\sqrt[]{(x_S-x_T)^2+(y_S-y_T)^2_{}},$

where (xS,yS) are the coordinates of the point S and (xT,yT) are the coordinates of the point T.

Replacing the coordinates of the points in the formula above, we find that:

$\begin{gathered} ST=\sqrt[]{(-3_{}-(-2)_{})^2+(10_{}-3_{})^2_{}}, \\ ST=\sqrt[]{1^2+7^2}, \\ ST=\sqrt[]{50}\text{.} \end{gathered}$

Answer: ST = √50

3 0

3 months ago

Find P 20 of the following arithmetic sequence: 206, 212, 218, 224....

Yanka [14]

Answer:

$p_{20} = 1.25528$

P₀ = 206 and difference d = 6

Step-by-step explanation:

Step(i):-

Given that the arithmetic sequence

206,212,218,224,.....

P₀ = 206 and difference d = 212-206 = 6

The $n^{th}$ term of the sequence

$t_{n} = ar^{n-1}$

Step(ii):-

The $n^{th}$ term of the sequence

$P_{n} = ar^{n-1}$

Put n=20

$P_{20} = 206 ( 6) ^{20-1}$

$p_{20} = 1.25528$

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2 years ago