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Alex73 [517]
3 years ago
11

Measure of missing angle ???

Mathematics
1 answer:
Anastasy [175]3 years ago
5 0

Answer:

b. 50°

Step by Step:

100+30+x=180

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Can you please help me understand how to solve a trig ratio like this?
yKpoI14uk [10]

Answer:

cos47° = \frac{x}{7}

Step-by-step explanation:

cos47° = \frac{adjacent}{hypotenuse} = \frac{x}{7}

6 0
3 years ago
Find the equation of the line that passes through the point (3,7) and is parallel to the line that passes through (5,5) and (5,3
Vinil7 [7]

Answer:

this is correct answer

Step-by-step explanation:

you supports to write this

7 0
3 years ago
Ok last question then im done
kkurt [141]
55.. i am pretty sure. if i’m wrong you could slap me
4 0
3 years ago
Read 2 more answers
Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11
Alexus [3.1K]

Answer:\frac{-7\sqrt{2} }{4}

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get \sqrt{16}-x\sqrt{8} =11. We know that the square root of 16 is ±4, so now our equation is ±4 - x\sqrt{8}=11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - x\sqrt{8}=11. We can use inverse operations to make the a little easier to solve: -7= x\sqrt{8}. We divide both sides by \sqrt{8} to get \frac{-7}{\sqrt{8} } =x, which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by \frac{\sqrt{8} }{\sqrt{8} } (which is equal to one so we can use it) which is equal to \frac{-7\sqrt{8} }{8}. Let's finish this by simplifying it. \sqrt{8} =2\sqrt{2} (2x2^{2}). We can simplify it further by simplifying the 2, making it \frac{-7\sqrt{2} }{4}.

Hope this wasn't too confusing! I'll answer any questions.

8 0
3 years ago
Read 2 more answers
I need help on a question
schepotkina [342]

Given the figure of a regular pyramid

The base of the pyramid is a hexagon with a side length = 6

The lateral area is 6 times the area of one of the side triangles

So, the side triangle has a base = 6

The height will be:

\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}

so, the lateral area =

6\cdot\frac{1}{2}\cdot6\cdot\sqrt[]{63}=18\sqrt[]{63}

3 0
1 year ago
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