Measure of missing angle ???

Which statement is true about the angles?

liq [111]

Complete Question:

Triangle abc has the angle mesausres shown.

m<A = (2x)°

m<B = (5x)°

m<C = (11x)°

Which statement is true about the angles?

A. m<A = 20°

B. m<B = 60°

C. m<A and m<B are complementary

D. m<A + m<C = 120°

Answer:

A. m<A = 20°

Step-by-step explanation:

m<A + m<B + m<C = 180° (sum of interior angles of a triangle)

$2x + 5x + 11x = 180$ (substitution)

Solve for x. Add like terms.

$18x = 180$

Divide both sides by 18

$\frac{18x}{18} = \frac{180}{18}$

$x = 10$

Find the measure of each angle by substituting x = 10:

m<A = (2x)° = 2(10) = 20°

m<B = (5x)° = 5(10) = 50°

m<C = (11x)° = 11(10) = 110°

Therefore, the only true statement is:

A. m<A = 20°

3 0

3 years ago

Read 2 more answers

A metal rod is placed in a rectangular box as shown in the figure. How long is the rod? Round your answer to the nearest tenth o

Alexandra [31]

Fist we find the legnth of the diagonal
a^2+b^2=c^2
3^2+4^2=c^2
9+16=c^2
25=c^2
c=5

now the other diagonal
11^2+5^2=c^2
121+25=c^2
146=c^2
sqrt both sides12.083
closest is B

7 0

3 years ago

A company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that

kondaur [170]

Answer:

Probability that the company wins project A or project B is 0.50.

Step-by-step explanation:

We are given that a company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that the company wins project B is 0.25.

Also, Winning project A and winning project B are independent events.

Let the Probability of winning project A = P(A) = 0.40

Probability of winning project B = P(B) = 0.25

Now, as we know that ;

Probability that the company wins project A or project B = $P(A \bigcup B)$

$P(A \bigcup B) = P(A) + P(B) - P(A \bigcap B)$

So, we have to find the value of Probability of winning project A and B, i.e;

$P(A \bigcap B)$

Since, we are given that Winning project A and winning project B are independent events which means when this condition is given then;

$P(A \bigcap B) = P(A) \times P(B)$

= 0.40 $\times$ 0.25 = 0.10

Now, Probability that the company wins project A or project B is given by;

$P(A \bigcup B) = P(A) + P(B) - P(A \bigcap B)$

= 0.40 + 0.25 - 0.10

= 0.65 - 0.10 = 0.55

Hence, probability that the company wins project A or project B is 0.50.

3 0

3 years ago

Write in expanded form 1) 531.029

Paraphin [41]

Answer:

expanded for everything

Step-by-step explanation:

Expanded Form of 531.029:

531.029 = (5 * 102) + (3 * 101) + (1 * 100) + (2 * 1/102) + (9 * 1/103)

531.029 = (5 * 100) + (3 * 10) + (1 * 1) + (2 * 1/100) + (9 * 1/1,000)

531.029 = 500 + 30 + 1 + 2/100 + 9/1,000

531.029 = 500 + 30 + 1 + 0.02 + 0.009

4 0

3 years ago

A group of 7 people spent $33.50 on movie tickets. They paid $6.50 for each adult ticket and $3.50 for each child's ticket. We w

rewona [7]

Answer:

Number of Adult tickets = 3

Number of student tickets = 4

Step-by-step explanation:

Let the number of Adults tickets = x

The number of students tickets = y

A. Specifically define variables for this system

x + y = 7...... Equation 1

They paid $6.50 for each adult ticket and $3.50 for each child's ticket.

$6.50 × x + $3.50 × y = $33.50

6.50x + 3.50y = 33.50.......Equation 2

B. Write a system of equations that reflects the relationships described in this situation

x + y = 7...... Equation 1

x = 7 - y

6.50x + 3.50y = 33.50.......Equation 2

6.50(7 - y) + 3.50y = 33.50

45.5 - 6.5y + 3.5y = 33.5

45.5 - 33.5 = 6.5y -3.5y

12 = 3y

y = 12/3

y = 4 tickets

x + y = 7...... Equation 1

x + 4 = 7

x = 7- 4

x = 3 tickets

6 0

3 years ago