So one key thing to remember here is that the direction of the correlation is irrelevant, that is it does not matter if your correlation is + or - what matters is how close that number is to 1.0.
To help you out here are the ranges of correlation strength
- 0.70. A strong relationship
- 0.50. A moderate relationship
- 0.30. A weak relationship
So to start off with 0.26 and 0.18 are very small correlations so you'd call those weak correlations.
Let me know if you need help doing the other ones? It should be simple enough with the data I gave you :)
Move the -4 to the right (+4 on both sides). now you have 4y=20. divide both sides by 4. y=5
Answer:
9.42
Step-by-step explanation:
The circumference of a circle is calculated using the following formula:
C=2πr (C: circumference, r : radius)
radius here is 6 and π is given as 3.14
2*(3.14)*6 = 18.84 now divide this by 2 to find the length of semicircle
18.84/2 = 9.42
Answer:
The equation does not have a real root in the interval ![\rm [0,1]](https://tex.z-dn.net/?f=%5Crm%20%5B0%2C1%5D)
Step-by-step explanation:
We can make use of the intermediate value theorem.
The theorem states that if
is a continuous function whose domain is the interval [a, b], then it takes on any value between f(a) and f(b) at some point within the interval. There are two corollaries:
- If a continuous function has values of opposite sign inside an interval, then it has a root in that interval. This is also known as Bolzano's theorem.
- The image of a continuous function over an interval is itself an interval.
Of course, in our case, we will make use of the first one.
First, we need to proof that our function is continues in
, which it is since every polynomial is a continuous function on the entire line of real numbers. Then, we can apply the first corollary to the interval
, which means to evaluate the equation in 0 and 1:

Since both values have the same sign, positive in this case, we can say that by virtue of the first corollary of the intermediate value theorem the equation does not have a real root in the interval
. I attached a plot of the equation in the interval
where you can clearly observe how the graph does not cross the x-axis in the interval.
To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.