Question

suppose a population is carrying a condition controlled by two alleles R (dominant) and r (recessive). if the frequency of the r allele is 15% and the frequency of the R allele is 85%. what will be the frequency of the RR genotype ,assuming evolution is not occuring?

Answer 1

I believe it's 72.25%

Answer 2

Answer:

Frequency of the RR $= 72.25$%

Explanation:

Given -

R is the dominant allele and r is the recessive allele.

The frequency of the r allele is $15$%$= 0.15$

The frequency of the R allele is $85$%$= 0.85$

As per Hardy Weinberg's equation-

$p = 0.85$

$q = 0.15$

Also, evolution is not occurring is the basic assumption of Hardy Weinberg's principle.

Frequency of the RR genotype is equal to $p^{2}$

Substituting the value of "p" we get

$p^{2} = 0.85^{2} \\= 0.7225\\= 72.25$