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Alex Ar [27]
4 years ago
11

What’s the area of a circle if the diameter is 80

Mathematics
2 answers:
aleksley [76]4 years ago
8 0

The area of a circle if the diameter is 80 is

A=5026.55

noname [10]4 years ago
7 0
The area of a circle is pi * radius squared. the diameter of a circle is two times the radius, so the radius of this circle is 40. so the area of this circle is 40^2 times pi, which is about 5026.55.
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If EF=2x-5, FG=3x-6, and EG=19 find the values of x, EF, and FG. The drawing is not to scale.
Tom [10]
EG is the whole thing.
This means that EF + FG = EG

<span>EF=2x-5
</span><span>FG=3x-6
</span><span>EG=19

Now all you do is plug in the numbers.
(2x - 5) + (3x - 6) = 19
5x - 11 = 19
5x = 30
x = 6

Now plug that x into EF and FG.
</span>EF = 2x - 5
EF = 2(6) - 5
EF = 12 - 5
EF = 7

FG = 3x - 6
FG = 3(6) - 6
FG = 18 - 6
FG = 12

So your answers are:
x = 6
EF = 7
FG = 12
<span>d. x = 6, EF = 7, FG = 12</span>
5 0
3 years ago
HELP ME!! What is the number of terms in this expression?<br><br> m/5+4⋅6
Kitty [74]

Answer:

eek, m/5+120??

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

6 0
4 years ago
PLEASE HELP!!
Sergeeva-Olga [200]

Answer:

and the addition will be p+q

Step-by-step explanation:

the diffrence between p and q is u have to add so the answer will be p-q

7 0
3 years ago
The senior class want to play a practical joke on the principal, who was a former college basketball star. They want to fill his
steposvetlana [31]

The number of basketball that will fill up the entire office is <u>approximately 16,615.</u>

<em><u>Recall:</u></em>

Volume of a spherical shape = \frac{4}{3} \pi r^3

Volume of a rectangular prism = l \times w \times h

<em><u>Given:</u></em>

Diameter of basketball = 9.5 in.

Radius of the ball = 1/2 of 9.5 = 4.75 in.

Radius of the ball in ft = 0.4 ft (12 inches = 1 ft)

Dimension of the office (rectangular prism) = 20 ft by 18 ft by 12 ft

  • First, find the volume of the basketball:

Volume of ball = \frac{4}{3} \pi r^3 = \frac{4}{3} \times \pi \times 4.75^3\\

Volume of basketball = 448.92 $ in^3

  • Convert to ft^3

1728 $ in.^3 = 1 $ ft^3

<em>Therefore,</em>

  • Volume of basketball = \frac{448.92}{1728} = 0.26 $ ft^3

  • Find the volume of the office (rectangular prism):

Volume of the office = 20 \times 18 \times 12 = 4,320 $ ft^3

  • Number of basket ball that will fill the office = Volume of office / volume of basketball

  • <em>Thus:</em>

Number of basket ball that will fill the office = \frac{4,320}{0.26} = 16,615

Therefore, it will take approximately <u>16,615 balls</u><u> to fill up the entire office</u>.

Learn more here:

brainly.com/question/16098833

6 0
3 years ago
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