Answer:
![\sqrt{x}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D)
Step-by-step explanation:
If we have that worded expression, we can convert it into actual mathematical terms.
x to the one sixth power: ![x^{\frac{1}{6}}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
That to the power of 3:
![(x^{\frac{1}{6}})^3](https://tex.z-dn.net/?f=%28x%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%29%5E3)
Using exponent rules, since we have a power to a power, the powers multiply, so:
![x^{\frac{1}{6}\cdot 3}\\\\x^{\frac{3}{6}}\\\\ x^{\frac{1}{2}}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B1%7D%7B6%7D%5Ccdot%203%7D%5C%5C%5C%5Cx%5E%7B%5Cfrac%7B3%7D%7B6%7D%7D%5C%5C%5C%5C%20x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
If we have a number to a fraction power, the denominator becomes the “find the (denominator) root of x.
So:
![x^{\frac{1}{2}} = \sqrt{x}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Csqrt%7Bx%7D)
Hope this helped!
Independent Events are 2 events where the occurrence of the first doesn't affect the occurrence of the second and vice versa.
Example: rolling 2 simultaneously dies, the occurrence of the first, has no impact, no effect on the occurrence of the 2nd roll
2 1/3+ 3 5/6+ 6 2/3
= 7/3+ 23/6+ 20/3
= 14/6+ 23/6+ 40/6
= 77/6
= 12 5/6
The final answer is 12 5/6~
Answer:
the answer is the second one:
ordered pair (2,-2) ; y-intercept -4
Step-by-step explanation:
hoped that helped
You would need to know the dimensions of the pyramid and wether it was triangle or square bottomed