Given:
Irregular Shape:
Semi-circle and rectangle:
Area of a rectangle = l * w
Area of a semi-circle = (π r²)/2
Area of rectangle = 8 cm * 5 cm = 40cm²
Area of a semi-circle = (3.14 (4²))/2 = (3.14*16)/2 = 50.24/2 = 25.12cm²
4² is taken from diameter of 8cm divided by 2 to get the radius.
Total area = 40 cm² + 25.12 cm² = 65.12 cm²
Answer:
3,200
Step-by-step explanation:
3 is less than 5 so you round down to 3,200
Answer:
m∠DEC = 78°
Step-by-step explanation:
Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.
If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.
AC = AD (Given)


According to the angle sum property, the sum of interior angles of a triangle is 180°.




Divide both sides by 2.

CE bisects ∠ACD.



Use angle sum property in triangle CDE,




Subtract 102 from both sides.


Therefore, the measure of angle DEC is 78°.
Answer:
Sorry, the question doesn't make sense. But Measure of angle A is28 degrees. what are you trying to figure out for just A and C?
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given


Required
Determine LN
Since LM is a bisector, then we have:
(See attachment for illustration)

Collect Like Terms


Solve for w


LN is calculated as thus:

Substitute 4 for w


