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3 years ago

Drag each equation to show if it could be a correct first step to solving the equation 3(6+x)=24

Mathematics

2 answers:

kakasveta [241]3 years ago

5 0

Use the distributive property.

3(6 + x) = 24

18 + 3x = 24

3x = 6

x = 2

jolli1 [7]3 years ago

5 0

Answer:

x=2

Step-by-step explanation:

3(6+x)=24

Divide both sides by 3.

6+x=24/3

Divide 24 by 3 to get 8.

6+x=8

Subtract 6 from both sides.

x=8−6

Subtract 6 from 8 to get 2.

x=2

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A study of 10 different weight loss programs involved 500 subjects. Each of the 10 programs had 50 subjects in it. The subjects

Yakvenalex [24]

Answer:

a) (iii) ANOVA

b) The ANOVA test is more powerful than the t test when we want to compare group of means.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $p=10$ groups and on each group from $j=1,\dots,p=10$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

Solution to the problem

Part a

(i) confidence interval

False since the confidence interval work just when we have just on parameter of interest, but for this case we have more than 1.

(ii) t-test

Can be a possibility but is not the best method since every time that we conduct a t-test we have a chance that we commit a Type I error.

(iii) ANOVA

This one is the best method when we want to compare more than 1 group of means.

(iv) Chi square

False for this case we don't want to analyze independence or goodness of fit, so this one is not the correct test.

Part b

The ANOVA test is more powerful than the t test when we want to compare group of means.

8 0

4 years ago

A manufacturer knows that their items have a normally distributed length, with a mean of 16.2 inches, and standard deviation of

statuscvo [17]

Answer:

57.926%

Step-by-step explanation:

Calculation for the probability that it is less than

16.4 inches long

Using this formula

z = (X - μ) / σ

Where,

X represent Date=16.4

μ represent Mean=16.2

σ represent Standard deviation=0.9 inches

Let plug in the formula

z = (16.4 - 16.2) /0.9 inches

z=0.2/0.9 inches

z = 0.2

Using Z-score table to find the area of 0.2

z=0.57926*100

z=57.926%

Therefore the probability that it is less than

16.4 inches long is 57.926%

6 0

3 years ago

What are expressions for MN and LN? Hint Construct the altitude from M to LN.

Nikitich [7]

The question is missing the figure. So, it is in the atachment.

Answer: MN = x $\sqrt{2}$ LN = $\frac{x}{2}.(\sqrt{2} + \sqrt{6} )$

Step-by-step explanation: The first figure in the attachment is the figure of the question. The second figure is a way to respond this question by tracing the altitude from M to LN as suggested. When an altitude is drawn, it forms a 90° angle with the base, as shown in the drawing. To determine the other angle, you have to remember that all internal angles of a triangle sums up to 180°.

For the triangle <u>on the left</u> of the altitude:

45+90+angle=180

angle = 45

For the triangle <u>on the right</u>:

30+90+angle=180

angle = 60

With the angles, use the Law of Sines, which is relates sides and angles, as follows:

$\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}$