What additional info is needed to prove Δ TUX congruent to Δ DEO by HL?
2 answers:
Answer:
1.
Step-by-step explanation:
We have been given two right triangles and we are asked to choose the correct option that is needed to prove Δ TUX congruent to Δ DEO by HL.
Since HL (Hypotenuse-Leg) congruence theorem states that if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.
We can see that in triangle TUX, UX is hypotenuse and in triangle DEO, EO is hypotenuse.
We have been given that hypotenuse of both triangle are equal, so to prove these triangles congruent by HL congruence either side length TU should be equal to side length DE or length of side TX should be equal to side DO.
Upon looking at our given choices we can see that only 1st option is correct.
Therefore, 1st option is the correct choice.
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Answer:
a) It can be used because np and n(1-p) are both greater than 5.
Step-by-step explanation:
Binomial distribution and approximation to the normal:
The binomial distribution has two parameters:
n, which is the number of trials.
p, which is the probability of a success on a single trial.
If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.
In this question:
So, lets verify the conditions:
np = 201*0.45 = 90.45 > 5
n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5
Since both np and n(1-p) are greater than 5, the approximation can be used.