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3 years ago

15

6/7 times 14/18=? show how you got the answer with supporting work.

1 answer:

Alexus [3.1K]3 years ago

8 0

Answer:

0.6666666667

Step-by-step explanation:

so in this case numerator can cancel the denominators and 7(d) and 14(n) can cancel also 6(n) and 18(d) when u do this u will get 2/3. u can decide to change to demical

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What is the length of side BC of the triangle? Enter your answer in the box. units Triangle A B C with horizontal side B C. Vert

harina [27]

Answer:

The length of BC = 28 units

Step-by-step explanation:

* In triangle ABC

∵ Angles B and C are congruent

∴ m∠B = m∠C

* In any triangle if two angles are equal in measure, then the triangle is isosceles means the two sides which opposite to the congruent angles are equal in length

∴ AB = AC

∵ AB = 4x - 7

∵ AC = 2x + 7

∴ 4x - 7 = 2x + 7 ⇒ collect like terms

∴ 4x - 2x = 7 + 7

∴ 2x = 14 ⇒ divide both sides by 2

∴ x = 14 ÷ 2 = 7

* Now we can find the length of BC

∵ The length of BC = 4x ⇒ substitute the value of x

∴ The length of BC = 4 × 7 = 28 units

6 0

3 years ago

A(n)=−6−4(n−1)<br> Find the 4th term in the sequence

blondinia [14]

If n = the term number, then:
A(4) = 6-4(4-1)
A(4) = 6-4(3)
A(4) = 6-12
A(4) = -6
A = -1.5

4 0

4 years ago

Multiple choice please answer please

faust18 [17]

Answer:

15/17

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

What is the sum of the sequence 152,138,124, ... if there are 24 terms?

N76 [4]

Answer: -216

Step-by-step explanation:

To solve the exercise you must use the formula shown below:

$Sn=\frac{(a_1+a_n)n}{2}$

Where:

$a_1=152\\a_n=a_{24}$

You should find $a_{24}$

The formula to find it is:

$a_n=a_1+(n-1)d$

Where d is the difference between two consecutive terms.

$d=138-152=-14$

Then:

$a_{24}=152+(24-1)(14)=-170$

Substitute it into the first formula. Therefore, you obtain:

$S_{24}=\frac{(152-170)(24)}{2}=-216$

3 0

4 years ago

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Use logarithmic differentiation to find the derivative of the function.y = x^8 sin(x)

givi [52]

$Answer: \frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})$

Step-by-step explanation:

Since we have given that

$y=x^{8sinx}$

By using logarithmic on both sides we get,

$log y= 8 sinx. logx$

(∵ $log(a^m)=m.loga$ )

Now, differentiating on both sides ,we get,

$\frac{1}{y}.\frac{\partial y}{\partial x}=8(\frac{\partial sinx}{\partial x}.logx+sinx \frac{\partial logx}{\partial x})$

$\\\frac{1}{y}\frac{\partial y}{\partial x}=8(cosx.logx+sinx.\frac{1}{x})$

$\\\frac{\partial y}{\partial y}=8y(cosx.logx+\frac{sinx}{x})\\\\\frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})$

6 0

3 years ago