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3 years ago

A bag contains the following marbles: 5

Mathematics

2 answers:

Inessa [10]3 years ago

5 0

Answer:

5:20

Step-by-step explanation:

There are 5 black marbles and 20 brown marbles.

You would put black marbles (5) first, because it came before brown (20) in the list.

Pani-rosa [81]3 years ago

3 0

20:5
20/5
The answer would be 4:1 or 4/1

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F(x+k) what is the value of k

guapka [62]

Answer:

k = -3

Hope this helps!

6 0

3 years ago

Read 2 more answers

For a school play, 739 tickets valued at $857 were sold. Some cost $1 and others cost a $1.50. How many $1 tickets were sold?

balu736 [363]

Answer:

503 $1 tickets sold.

Step-by-step explanation:

Use two equations

Let x = number of $1 tickets sold

Let y = number of $1.50 tickets sold

x + y = 739

1x + (1.5)y = 857

First equation ==> y = 739 - x

Plug this into the second equation

x + (1.5)(739 - x) = 857

x + 1108.5 - 1.5x = 857

- 0.5x = -251.5

x = 503

There were 503 $1 tickets sold.

To find the number of $1.50 tickets, just plug this value of x into either one of the equations.

(503) + y = 739 (739 - 503 = 236)

y = 236

There were 236 $1.50 tickets sold.

3 0

3 years ago

If 29% of the students wore jeans what percent of he students did not wear jeans?

igor_vitrenko [27]

So you just take 100% - 29% = 71%

So 71% of the students did not wear jeans

7 0

3 years ago

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

3 years ago

Read 2 more answers

What is k-15=-8?<br><br><br> I need help with this one<br> Btw it is asking what k equals.

LuckyWell [14K]

Answer:

k=7

Step-by-step explanation:

Add 15 to both sides, -8+15=7

So, K=7

4 0

3 years ago